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Katarina [22]
3 years ago
7

Pls help me solve this​

Physics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

a) The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car with uniform velocity is 100 meters.

Explanation:

a) Calculate the uniform velocity travelled by the car:

The uniform velocity is the final velocity (v), in meters per second, of the the uniform accelerated stage:

v = v_{o} + a\cdot t (1)

Where:

v_{o} - Initial velocity, in meters per second.

a - Acceleration, in meters per square second.

t - Time, in seconds.

If we know that v_{o} = 0\,\frac{m}{s}, a = 2\,\frac{m}{s^{2}} and t = 5\,s, then the uniform velocity is:

v = 0\,\frac{m}{s} + \left(2\,\frac{m}{s^{2}} \right)\cdot (5\,s)

v = 10\,\frac{m}{s}

The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car (\Delta x), in meters, with uniform velocity is calculated by the following kinematic expression:

\Delta x = v\cdot t (2)

If we know that v = 10\,\frac{m}{s} and t = 10\,s, then the distance travelled is:

\Delta x = \left(10\,\frac{m}{s} \right)\cdot (10\,s)

\Delta x = 100\,m

The distance travelled by the car with uniform velocity is 100 meters.

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Explanation:

Apply the Gay-lussacs's law we have

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Cross multiplying and making T2 subject of formula we have

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