£9 - 90p = £8.10
2 Pencils = 48p
3 Pens = £1.11
3 Sharpeners = £2.31
All together = £3.90
£8.10 - £3.90 = £4.20
£4.20 / £1.40 = 3
Answer = 3 Notebooks
You mean situation, when a^b < a.
There are two ways:
![a^b < a^1 \\ b](https://tex.z-dn.net/?f=a%5Eb%20%3C%20a%5E1%20%5C%5C%20b%3C1%20)
But exponent function a^b has to be increasing so a>1
So first solution: a>1 and 0<b<1. Examples:
![5^{\frac{1}{2}} < 5 \\ 120^{\frac{1}{12}} < 120](https://tex.z-dn.net/?f=5%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3C%205%20%5C%5C%20120%5E%7B%5Cfrac%7B1%7D%7B12%7D%7D%20%3C%20120)
and second way:
![a^b < a^1 \\ b>1](https://tex.z-dn.net/?f=a%5Eb%20%3C%20a%5E1%20%5C%5C%20b%3E1)
Exponent function a^b has to be decreasing, so 0<a<1
Second solution: a<1 and b>1. Examples:
7/4 minus 4/6 is 1 and 1/12
3/10 minus 1/5 is 1/10
5/4 minus 5/12 is 5/6
you should use caculator soup!
(a^3b)^2 • 4ab^3
a^6b • 4ab^3
4a^6b+1b^3
Answer:
E
Step-by-step explanation:
The average rate of change of A(x) in the closed interval [ a, b ] is
![\frac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
Here [ a, b ] = [ - 4, 6 ] , then
f(b) = f(6) = 6² + 2(6) + 3 = 36 + 12 + 3 = 51
f(a) = f(- 4) = (- 4)² + 2(- 4) + 3 = 16 - 8 + 3 = 11 , thus
average rate of change =
=
= 4 → E