Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
Answer:
Option "D" is correct $3630
Step-by-step explanation:
At the beginning of the 7th year, the money has been in the account for 6 years.
The simple interest on $3000 at 3.5% for 6 years is I = prt:
(3000) = (.035) = (6) = 360
he amount in the account at the <u>beginning of the 7th year</u> is then the <u>original amount plus</u> the interest <u>$3630.</u>
Answer:
A and D
Step-by-step explanation:
We are given that
(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)
k=
Direct proportion:
Inverse proportion:
Therefore, it is not in direct proportion.
Therefore,
Hence, the given points form an inverse variation .
Option A and D is true.
Answer:
picture?
Step-by-step explanation: