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monitta
3 years ago
15

Which group of elements have some properties of metals and some properties of nonmetals?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
The group of elements that have some properties of metals and some properties of nonmetals are called metalloids.
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On the periodic table, calcium and bromine are located in period 4. What is one difference between the two elements?
Dovator [93]

Answer:

D

Explanation:

Just look at the groups and their tendencies. Or look at their electron configurations. You will notice that calcium has 2 valence electrons and bromine has 7 valence electrons.

Halogens have the most valence electrons possible without completing a shell (8 would be needed for that)

4 0
2 years ago
Kathleen makes iced coffee by adding ice to her room temperature coffee in a glass. What statement explains what is taking place
Ganezh [65]

Answer:

The answer is the heat is transferred from the ice to the coffee.

Explanation:

Hot molecules tend to transfer to colder molcules, which causes the ice to melt and makes the coffee colder.

Hope this helps! :)

3 0
1 year ago
What masses of kbr and water are needed to produce 300. g of a solution that is 3.00 % by mass?
attashe74 [19]
In a solution of KBr and water; KBr is the solute and water is the solvent;
Therefore; to achieve 3% by mass; it means we are going to have 3% of the mass being the solute and the other 97 % being the solvent.
Thus; KBr (solute) = 3/100 × 300 (total mass) = 9 g
Hence; the appropriate masses will be; 9.00 g of KBr and 291 g of water.
8 0
2 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
2 years ago
Can a cold front warm air moves which direction
Katena32 [7]
East is the cold front
6 0
3 years ago
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