Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid. ... In SI units, pressure is measured in pascals; one pascal equals one newton per square metre. Atmospheric pressure is close to 100,000 pascals.
<h3>#CarryOnLearning</h3>
Answer:
a

b
Horizontal component
vertical component

c

d

Explanation:
Generally from the question we can deduce that he initial velocity of the cork, as seen by an observer on the ground in terms of the x unit vector is
due to the fact that the cork is moving horizontally
Generally from the question we can deduce that the vertical and horizontal components of the initial velocity is
due to the fact that the balloon is moving downward which is the negative which will also cause the cork to move vertically with the balloon speed
Generally the initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground is mathematically represented as



Generally the initial direction of motion as seen by the same observer is mathematically represented as
![\theta = tan^{-1}[\frac{2}{5} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B2%7D%7B5%7D%20%5D)

Generally the time taken by the cork in the air before landing is mathematically represented as

So D = 6 \ m from the question
g = 9.8 \ m/s^2
u =
= 2 m/s this because we are considering the vertical motion
So


Solving using quadratic formula w have that

Generally the distance of the cork from the balloon is mathematically represented as



- <em>S</em><em>peed </em><em>=</em><em> </em><em>8</em><em> </em><em>m/</em><em>s</em>
- <em>Distance</em><em> </em><em>=</em><em> </em><em>3</em><em>2</em><em> </em><em>m</em>
<u>We need to find time</u>
<h3>
We know that ,</h3>

<h3>
So ,</h3>

<h3>
<u>Substuting</u><u> the</u><u> values</u></h3>

Answer: 
Explanation:
Given
final velocity at takeoff 
Acceleration of the plane can be 
Initial velocity is zero for the plane i.e. 
Using the equation of motion
![\Rightarrow v^2-u^2=2as\quad [\text{s=displacement}]\\\text{Insert the values}\\\Rightarrow (28.1)^2-0=2\times 2\times s\\\\\Rightarrow s=\dfrac{789.61}{4}\\\\\Rightarrow s=197.40\ m](https://tex.z-dn.net/?f=%5CRightarrow%20v%5E2-u%5E2%3D2as%5Cquad%20%5B%5Ctext%7Bs%3Ddisplacement%7D%5D%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5CRightarrow%20%2828.1%29%5E2-0%3D2%5Ctimes%202%5Ctimes%20s%5C%5C%5C%5C%5CRightarrow%20s%3D%5Cdfrac%7B789.61%7D%7B4%7D%5C%5C%5C%5C%5CRightarrow%20s%3D197.40%5C%20m)
Thu,s the minimum length must be 
This statement is false.
When <span>phospholipids are placed on the surface of water they spontaneously form a bilayer.
A bilayer is defined as a structure that is formed of two molecular layers, especially in the cellular membranes of phospholipids.</span>