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saw5 [17]
3 years ago
13

Need help due tonight

Mathematics
1 answer:
Degger [83]3 years ago
5 0

Answer:

an=7n-19

(the last one)

Step-by-step explanation:

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A freight train from city A to city B and a passenger train from city B to city A left the cities at the same time, at 10:00 AM,
djyliett [7]

Answer: Both trains would meet at 1 pm

Step-by-step explanation:

Let t represent the time at which both trains will pass each other.

The distance between the cities is 360 miles. This means that by the time both trains meet, the total distance covered would be 360 miles.

Distance = speed × time

The freight train is travelling at 50 mph. Distance covered by the freight train in t hours is 50t.

The passenger train is travelling at 70 mph. Distance covered by the passenger train in t hours is 70t.

Since the total distance covered is 360 miles, it means that

50t + 70t = 360

120t = 360

t = 360/120

t = 3 hours

Both trains would meet at 1 pm

8 0
3 years ago
A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8
uysha [10]

Answer:

12

Step-by-step explanation:

Given :

                                    Male         Female        Total

Registered                                                          60

Non registered                                                   40

Total                          20                  80    

Solution :

N= 100

Formula of expected frequency = E_{ij}=\frac{T_i \times T_j}{N}

E_{ij}= expected frequency for the ith row/jth columm.

T_i = total in the ith row

T_j= total in the jth column

N = table grand total.

So, using formula  E_{11}=\frac{T_1 \times T_1}{100}

E_{11}=\frac{60 \times 20}{100}

E_{11}=12

E_{12}=\frac{T_1 \times T_2}{100}

E_{12}=\frac{60 \times 80}{100}

E_{12}=48

E_{21}=\frac{T_2 \times T_1}{100}

E_{21}=\frac{40 \times 20}{100}

E_{21}=8

E_{22}=\frac{T_2 \times T_2}{100}

E_{22]=\frac{80 \times 40}{100}

E_{22}=32

Expected frequency table

                                    Male         Female        Total

Registered                  12                  48            60

Non registered           8                   32             40

Total                           20                  80    

So, the expected frequency for males who are registered voters are  E_{11}=12

5 0
3 years ago
Is 49 a perfect square
Sholpan [36]
Yes, it is also a square number
8 0
3 years ago
Read 2 more answers
The proportion of items in a population that possess a specific attribute is known to be 0.45. a. If a simple random sample of s
yanalaym [24]

Answer: 0.05

Step-by-step explanation:

  • Sampling error is the error occurs by considering sample for study instead of entire population.

Given : The proportion of items in a population that possess a specific attribute is known to be 0.45.

Sample size : n= 100

Sample proportion of items in a population that possess a specific attribute : \hat{p}=0.48

Now, the formula to find the sampling error :

\text{Sampling error} =\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

\text{Sampling error} =\sqrt{\dfrac{0.48(1-0.48)}{100}}

=\sqrt{\dfrac{0.48(0.52)}{100}}\\\\=\sqrt{0.002496}\approx0.05

Hence, the sampling​ error =0.05

4 0
3 years ago
Witch expression represents a number 5 times the difference of 6 and 2
nikklg [1K]

Answer:

i think it is 20

Step-by-step explanation:

6-2=4

4×5=20

6 0
3 years ago
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