The answer is -1/16 or -0.0625, do you need to see work?
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
Answer:
(2,-1)
Step-by-step explanation:
Multiply first equation by 2:
10x + 2y = 18
Subtract the second equation from this so that the 2y terms cancel:
10x - 3x = 18 - 4
7x = 14
x = 2
Plug into first equation to find y:
5(2) + y = 9
10 + y = 9
y = -1
The answer is (2,-1)
Answer: x = 16, x = 8
Step-by-step explanation:
|a| > 0, there are two solutions
|a| = 0, there is one solution
|a| < 0, there are no solutions
So, in this problem, we have two solutions.
In absolute value, the expression inside can be equal to itself OR its opposite.
Ex: |y| = y, |y| = -y
So, we can write two equations:
x - 12 = 4, x = 16
-x+12 = 4, x = 8
Check: |16 - 12| = |4| = 4
Check: |8 - 12| = |-4| = 4
