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Ivanshal [37]
3 years ago
15

A rubber ball weighs 49 N.. a) What is the mass of the ball? (Answer: 5.0 kg). b) What is the acceleration of the ball if an upw

ard force of 69 N is applied? (Answer: 4.0 m/s/s). For a) I used the equation W = Fg = mg, which becomes 49 = m(9.8). This approximates m to 5.0 kg.
---
For b) I used the equation
ΣFy=Fa−W=ma
which becomes 69-49 = 20 N.
I then use equation F = ma which becomes 20 = 5.0a, which makes a
4.0m/s2
Physics
1 answer:
weqwewe [10]3 years ago
4 0
The answer you presented is correct.

For a) I used the equation W = Fg = mg, which becomes 49 = m(9.8). This approximates m to 5.0 kg.
<span>For b) I used the equation
</span><span>ΣFy=Fa−W=ma</span> which becomes 69-49 = 20 N.
I then use equation F = ma which becomes 20 = 5.0a, which makes a <span>4.0m/<span>s2</span></span>
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7 0
3 years ago
If 90 grams of gold has a volume of 5 cm3, calculate the density (include the units and show your work or you get no credit
ehidna [41]

Answer:

The density of gold is of 18 grams per cm3.

Explanation:

The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:

90/5 = X

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6 0
3 years ago
I don't understand this QUESTION​
alex41 [277]

This electric force calculator will enable you to determine the repulsive or attractive force between two static charged particles. Continue reading to get a better understanding of Coulomb's law, the conditions of its validity, and the physical interpretation of the obtained result.

How to use Coulomb's law

Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges. It is repulsive if both charges have the same sign and attractive if they have opposite signs.

Coulomb's law is formulated as follows:

F = keq₁q₂/r²

where:

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q₁ is the magnitude of the first charge (in Coulombs),

q₂ is the magnitude of the second charge (in Coulombs),

r is the shortest distance between the charges (in m),

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6 0
2 years ago
Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j
Mnenie [13.5K]

The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

I₁ = current in wire 1

=0.40 A.

I₂ = current in wire 2

= -0.73 A.

We have to calculate the magnitude of the current in wire 3, I₃

Now we put the known values in above equation, we get,

I₁ + I₂ + I₃ = 0

Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

Or, I₃ = 0.33 A

From the above calculation, we can conclude that the current in wire 3 is  I₃ = 0.33 A

Learn more about current:

brainly.com/question/25537936

#SPJ4

7 0
1 year ago
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