4 years ago

Which layer contains solid rock and magma

Physics

1 answer:

BlackZzzverrR [31]4 years ago

3 0

The semi surface of earth

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A distance of 2.00 mm separates two objects of equal mass. If it gravitational force between them is 0.0104 N, find the mass of

Radda [10]

Put values in this formula, you will get the answer.

F=Gm^2/r^2

G=6.67X10^-11

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4 years ago

A proton is released from rest in a uniform electric field. After the proton has traveled a distance of 10.0 cm, its speed is 1.

GREYUIT [131]

Answer:

Explanation:

distance travelled s = 10 cm

speed v = 1.4 x 10⁶ m /s

v² = u² + 2as

u = 0

v² = 2as

( 1.4 x 10⁶ )² = 2 x a x .10

a = 9.8 x 10¹² m /s²

force on proton = mass x acceleration

= 1.67 x 10⁻²⁷ x 9.8 x 10¹²

= 16.366 x 10⁻¹⁵ N .

If magnitude of electric field be E

force on proton

= E x charge on proton

= E x 1.6 x 10⁻¹⁹

E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵

E = 10.22 x 10⁴ N/C

The direction of electric field will be positive x - direction .

b )

Speed of proton = 1.4 x 10⁶ m /s .

6 0

3 years ago

A flashlight is powered by 4, 1.5-volt batteries, which are connected in series. The bulb draws 720mA or 0.72 amps when turned o

Varvara68 [4.7K]

R=0.12
Use the equation V=I/R
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4 years ago

A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in

olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision $V_f =$ 262.41 $\frac{m}{s}$

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet $V_0$ = 266 $\frac{m}{s}$

Final velocity of whole system is

$V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}$

Put all the values in above formula we get

$V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}$

$V_f =$ 262.41 $\frac{m}{s}$

This is the value of speed of wooden block at the instant after the collision.

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3 years ago

What is the area under the curve for the histogram below

igor_vitrenko [27]

Answer: B srry if i'm wrong

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2 years ago