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3 years ago

An engineer is designing a runway for an airport. Of the planes that will

Physics

1 answer:

ziro4ka [17]3 years ago

8 0

Answer:

704m

Explanation:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration a=3m/s 2

If d be the allowed length for the runway.

Using formula v*2 −u*2 =2aS

(65)*2−0*2 =2(3)d

⟹ d=65*2 /6=704.16∼704m

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How to find initial velocity

Vaselesa [24]

Answer:

Velocity= Distance divided by time divided by degree or direction.

Explanation:

Speed=DIstance divided by time

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3 years ago

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Why does a hot air balloon fall when the air inside is not heated

trapecia [35]

A hot air balloon rises in the first place because the air inside is hot, which rises. So, if the air inside is not heated, it fails to rise and falls. Warm air rises because the particles get excited and jiggle with the heat, and cause the air to take up more space. So, as the surrounding air is probably colder and denser, the less dense hot air rises up in the hot air balloon.

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4 years ago

Newton’s third law is the law of

matrenka [14]

Answer:

B. interactive

Explanation:

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3 years ago

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A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in

xz_007 [3.2K]

The answer:
the full question is as follow:
A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in Figure below , where A = 4.90 km and θC = 15°. He then correctly calculates the length and orientation of the fourth side D. What is the magnitude and direction of vector D?

As shown in the figure,
A + B + C + D = 0, so to find the magnitude and direction of vector D, we should follow the following method:
D = 0 - (A + B + C) ,
let W = - (A + B + C), so the magnitude and direction of vector D is the same of the vector W characteristics

Magnitude
A + B + C = (4.90cos7.5 - 2.48sin16 - 3.02cos15)I
+ (-4.9sin7.5 + 2.48cos16 + 3.02sin15)J
= 1.25I +2.53J
the magnitude of W= abs value of (A + B + C) = sqrt (1.25² + 2.53²)
= 2.82

the direction of D can be found by using Dx and Dy value
we know that tanθo = Dx / Dy = 1.25 / 2.53 =0.49
tanθo =0.49 it implies θo = arctan 0.49 = 26.02°

direction is 26.02°

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3 years ago

Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

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3 years ago