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Brums [2.3K]
3 years ago
7

Name the salts formed:

Chemistry
1 answer:
daser333 [38]3 years ago
6 0

Answer:

1)magnesium nitrate +hydrogen

2)calcium chlorine+hydrogen

3)zinc sulfate +hydrogen

Explanation:

hope it helps

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ILL GIVE YOU BRAINLIST * have to get it right * !!! Although individual body systems can perform specific functions, they depend
andre [41]
I think it might be A muscles help move nutrients through the body to the stomach
7 0
3 years ago
Can someone help pls
zysi [14]
What is the problem u need help with
3 0
2 years ago
For a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k, calculate the inner diameter if you are designing for
bonufazy [111]

The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m

<h3>What is Stack Height ?</h3>

Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.

If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.

Given is a steel stack that exhausts 1,200 cu.m/min of gases

P= 1 atm and

T= 400 K

maximum expected wind speed at stack height of 12 m/s

The formula for the diameter of chimney

\rm d=\sqrt{\dfrac{4Q}{\pi v} }

Q =1200 cu.m/min

= 1200 * 0.0166 = 19.92 cu.m/sec

Velocity = 12m/s

\rm d=\sqrt{\dfrac{4\times 19.92}{3.14*12} }\\

d= 1.45 m

Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.

To know more about Stack Height

brainly.com/question/24625453

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8 0
2 years ago
Identify each statement as true or false. Explain in every case.a.Ionization energies are always negative quantities.b.Oxygen ha
worty [1.4K]

Answer:

(a) FALSE

(b) FALSE

(c) TRUE

(d) FALSE

Explanation:

Ionization energy refers to the energy needed for removal of a valence electron present in valence shell of a gaseous atom.

(a) <u>The value of ionization energy of an atom is always</u><u> positive</u>. This is because energy has to be always supplied or provided to a gaseous atom for the removal of the valence electron.

<em><u>Therefore, the statement (A) is</u></em><em><u> false</u></em>

   

(b) The ionization energy of an atom <u>increases across a period</u> i.e. from left to right. This is because the <u>effective nuclear charge that is experienced by the valence electron increases</u> from left to right in the periodic table, as the atomic number increases.

So, more energy is required to remove the valence electron of fluorine as compared to oxygen.

<u>Therefore, the </u><u>ionization energy of fluorine is greater than oxygen</u><u>.</u>

<em><u>Therefore, the statement (B) is</u></em><em><u> false</u></em>

(c) <u>First ionization energy</u> is energy needed for removal of first electron present in valence shell of a neutral atom. Whereas, <u>second ionization energy</u> is the energy needed for removal of second electron present in valence shell of a monovalent cation

The second ionization energy of an atom is always greater than the first ionization energy. This is because removing<u> an electron from a positively charged species, requires more energy.</u>

<em><u>Therefore, the statement (C) is</u></em><em><u> true</u></em>

<em><u /></em>

(d) <u>The third ionization energy </u>refers to the energy needed to remove the third electron from a divalent cation.

<em><u>Therefore, the statement (D) is</u></em><em><u> false</u></em>

7 0
3 years ago
How many particles are in 47.7 g of Magnesium? (Round the average
Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0
2 years ago
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