Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Answer:
All carbons in the carbon skeleton contain the maximum number of hydrogen atoms
Explanation:
Saturated fats are class of compounds having all the fatty acids containing only single bonds. In other words, carbon skeleton has only single bonds.
Unsaturated compounds undergoes hydrogenation to form saturated fats.
In hydrogenation, hydrogen atoms are added to the carbon attached to double bond. After become saturated, no more hydrogen atoms can be added.
Therefore, it can be said that in saturated fats all carbons in the carbon skeleton contain the maximum number of hydrogen atoms.
Answer:
A chemical equation can be described as a symbolic representation of a chemical reaction. It can be written in the form of words or symbols.
The following chemical reaction can be completed as :
Na2SO4·10H2O + 2C = Na2S + 10H2O + 2CO2
Sodium Sulfate Decahydrate + Diamond = Sodium Sulfide + Water + Carbon Dioxide
The products of the reaction are:
- Sodium Sulfide (Na2S)
- Water (H2O)
The coefficients next to the symbols of entities indicate the number of moles of a substance produced or used in the chemical reaction.
