Answer:
x = -5, y = -6, z = -3
Step-by-step explanation:
Given the system of three equations:

Write the augmented matrix for the system of equations

Find the reduced row-echelon form of the augmented matrix for the system of equations:

Thus, the system of three equations is

From the last equation:

Substitute it into the second equation:

Substitute y = -6 and z = -3 into the first equation:

Jacob has 4 balloons, because 4 is half of 8
Hope this helps ya ;)
Answer: x = 7
Step-by-step explanation:
Subtract both sides by 3
X+3-3 = -4 - 3
X+0 = -7
X=-7
Answer:
Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...
2x2 + 7x = -3
2x2 + 7x + 3 = 0
Once the equation is in standard form, factor the quadratic expression.
2x2 + 7x + 3 = 0
(2x + 1)(x + 3) = 0
Using the Zero Product Property set each factor equal to 0 and solve for x.
2x + 1 = 0
2x + 1 - 1 = 0 - 1 x + 3 = 0
2x = -1 x + 3 - 3 = 0 - 3
2x 2 = -1 2 x = -3
x = -1 2
The solutions to the equation are -1 2 and -3.
A set that is closed under an operation or collection of operations is said to satisfy a closure
property.
For example, the set of even integer is closed under addition, but the set of odd integer is not.