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3 years ago

What is the volume of the rectangular prism?

Mathematics

2 answers:

mariarad [96]3 years ago

7 0

2x3x6 = 36 hope this helps!!

Iteru [2.4K]3 years ago

7 0

Rectangular prism is also called <u>cuboid</u>.

Length = 3 feet
Breadth = 6 feet
Height = 2 feet

<h3><u>To calculate :</u></h3>

Volume of the rectangular prism.

<h3><u>Calculations :</u></h3>

Formula :

$\bigstar \: \boxed{\sf {Volume_{(Cuboid)} = \ell \times b \times h}} \\$

$\longmapsto$ Volume = (3 × 6 × 2) feet $\sf ^3$

$\longmapsto$ Volume = (18 × 2) feet $\sf ^3$

$\longmapsto$ Volume = 36 feet $\sf ^3$

Therefore,

Volume of the rectangular prism is <u>36 feet $\sf ^3$ </u>.

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The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

x = 4500

$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

p = $45

6 0

3 years ago

Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)

raketka [301]

<h3>Answer is -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) ) = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

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3 years ago

Make r the subject of t = 6r^2 + 6

SpyIntel [72]

First step, divide 6 from both sides.

t/6=r^2+1

second step, subtract 1 from both sides

t/6 -1=r^2

Now take the square root of each side.

$\sqrt{\frac{t}{6}-1}=r$

Done!

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3 years ago

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It should cost 8 dollars all together.

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Katena32 [7]

Answer:

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Hope it helps

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2 years ago