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3 years ago

What is the volume of the rectangular prism?

Mathematics

2 answers:

mariarad [96]3 years ago

7 0

2x3x6 = 36 hope this helps!!

Iteru [2.4K]3 years ago

7 0

Rectangular prism is also called <u>cuboid</u>.

Length = 3 feet
Breadth = 6 feet
Height = 2 feet

<h3><u>To calculate :</u></h3>

Volume of the rectangular prism.

<h3><u>Calculations :</u></h3>

Formula :

$\bigstar \: \boxed{\sf {Volume_{(Cuboid)} = \ell \times b \times h}} \\$

$\longmapsto$ Volume = (3 × 6 × 2) feet $\sf ^3$

$\longmapsto$ Volume = (18 × 2) feet $\sf ^3$

$\longmapsto$ Volume = 36 feet $\sf ^3$

Therefore,

Volume of the rectangular prism is <u>36 feet $\sf ^3$ </u>.

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3 years ago

The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op

andreev551 [17]

<u>B) </u> $x =4.28$

<u>C) </u> volume = $135.25cm^3$ .

<u>Step-by-step explanation:</u>

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = $length(width)$

⇒ $Area = length(width)$

Putting values according to question we get :

⇒ $58 = (2x+5)(x)$

⇒ $58 = (2x^2+5x)$

⇒ $2x^2+5x - 58 = 0$

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒ $2x^2+5x - 58 = 0$

By quadratic formula

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}$

⇒ $x = \frac{-5 \pm 22.11}{4}$

⇒ $x = \frac{-5 + 22.11}{4} , x = \frac{-5 - 22.11}{4}$ { Since side can't be negative ! }

⇒ $x =4.28$

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

$2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28$

We know that volume is given by :

⇒ $length(width)(height)$

⇒ $13.86(4.28)(2.28)$

⇒ $135.25cm^3$

Therefore , volume = $135.25cm^3$ .

7 0

3 years ago

The width of a rectangle is 5 more than twice the length. the perimeter of the rectangle is 28 in. what is the length and width

ycow [4]

Perimeter is P = 2l + 2w. From the question you know that w = 2l + 5 and that P = 28. To find l, plug the expression for w into the perimeter equation:

28 = 2l + 2(2l + 5)

28 = 2l + 4l + 10

28 = 6l + 10

18 = 6l

3 = l

Now find w by plugging 3 into its equation - w = 2(3) + 5. w = 11

Lastly, check your work by plugging everything back into the perimeter equation: 28 = 2(3) + 2(11), which is 28 = 6 + 22. Correct! So the length is 3 in and the width is 11 in.

5 0

3 years ago