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Anestetic [448]
3 years ago
13

What is the degree of the simplest polynomial with integer coefficients that has √2 , 2 , √2 + i , and 2 + 2i as some of its zer

os?
a. 6
b. 7
c. 8
d. 9
Mathematics
1 answer:
Simora [160]3 years ago
8 0

If the polynomial has integer coefficients, then any complex roots with non-zero imaginary part must occur along with their conjugates. If <em>a</em> + <em>bi</em> is a root, then so is <em>a</em> - <em>bi</em>.

The given polynomial would then have at least 6 roots: √2, 2, √2 + <em>i</em> and √2 - <em>i</em>, and 2 + 2<em>i</em> and 2 - 2<em>i</em>. So the minimum degree is (A) 6.

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4%

To find the percentage, first find the area of both circles. The area formula is \pi  r^{2} . After finding the area of the center of the target (19.625) and the area of the large target (490.625), set up a percent proportion to determine the percentage that the center takes up: 

\frac{is}{of} =  \frac{percent}{100}


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3 years ago
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5 0
3 years ago
The difference between two numbers is 7194. If the subtrahend is 12,806, find the minuend.
valentina_108 [34]

<u>Answer:</u> The minuend is 20000

<u>Step-by-step explanation:</u>

To calculate the minuend, we use the equation:

\text{Subtrahend}=\text{Minuend-Difference}

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Putting values in above equation, we get:

\text{Minuend}=12806+7194\\\\\text{Minuend}=20000

Hence, the minuend is 20000

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3 years ago
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