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Fed [463]
2 years ago
11

To make 4.25 L of 3.0 M NaOH solution how much of a 9.0 M NaOH solution would be needed?

Chemistry
1 answer:
Elan Coil [88]2 years ago
4 0

Answer:

1.41 L

Explanation:

Initially the concentration of NaOH was 9.0M (say M1) finally the concentration becomes 3.0M (say M2)

intial volume (say V1) is to be calculated when the final volume (say V2) is 4.25L

we have,

M1V1=M2V2

or V1=(M2V2)/M1= 3.0×4.25/9.0= 1.41L

Hence 1.41 L of 9.0M solution is required to prepare 4.25L of 3.0M NaOH solution

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7 0
3 years ago
11.
vagabundo [1.1K]

Answer:

1.22 × 10^22 H atoms

Explanation:

From this question, TNT has the chemical formula: C-H5N306. The number of nitrogen atoms in the TNT substance is said to be 7.30 × 10^21 atoms.

The number of hydrogen atoms in the same TNT substance can be got using mole ratio. Based on the chemical formula, the mole ratio of hydrogen to nitrogen is 5:3 i.e. H5N3.

This means that;

Number of atoms of hydrogen = 5/3 of the number of atoms of nitrogen.

Hence, number of H atoms = 5/3 × 7.30 × 10^21

number of H atoms = (7.30 × 5/3) × 10^21

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number of H atoms = 12.1666 × 10^21

number of H atoms = 1.2166 × 10^22 atoms.

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