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Fed [463]
2 years ago
11

To make 4.25 L of 3.0 M NaOH solution how much of a 9.0 M NaOH solution would be needed?

Chemistry
1 answer:
Elan Coil [88]2 years ago
4 0

Answer:

1.41 L

Explanation:

Initially the concentration of NaOH was 9.0M (say M1) finally the concentration becomes 3.0M (say M2)

intial volume (say V1) is to be calculated when the final volume (say V2) is 4.25L

we have,

M1V1=M2V2

or V1=(M2V2)/M1= 3.0×4.25/9.0= 1.41L

Hence 1.41 L of 9.0M solution is required to prepare 4.25L of 3.0M NaOH solution

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sineoko [7]

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3 years ago
Which of the following is a statement of Hess's law?
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Answer:

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3 years ago
How many kilograms are 129.569grams?
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8 0
3 years ago
The density of pure silver is 10.5 g/cm3 at 20°C. If 5.25 g of pure silver pellets is added to a graduated cylinder containing 1
iren [92.7K]

Answer:

The correct answer is 16.6 mL

Explanation:

The density of a substance is defined as its mass per unit of volume. Thus:

density = mass/volume

So, to calculate volume: volume = mass/density

Given:

density= 10.5 g/cm³

mass= 5.25 g

We calculate the volume occupied by silver as follows:

volume= mass/density= (5.25 g)/(10.5 g/cm³)= 0.5 cm³

Moreover, we know that 1 cm³= 1 ml. So, a mass of 5.25 g of pure silver occupies a volume of 0.5 ml. If we add the mass of silver to a graduated cylinder with 16.1 mL of water, the final volume will be given by the initial volume of water plus the volume occupied by silver:

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3 years ago
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