0.06105 moles is the number of moles of water lost.
<h3>What is molar mass?</h3>
Molar mass is defined as the mass in grams of one mole of a substance.
Given data:
Mass of water = 1.1g
Molar mass water = 18.016 g/mol
Moles of water =?
These quantities are related by the following equation;
Moles = 
Substituting the values of the quantities and solving for moles, we have;
Moles = 
= 0.06105 moles.
Hence, the 0.06105 moles is the number of moles of water lost.
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Solution :
Given :
Initial temperature of the refrigerant is :
= ( 39.37 + 273 ) K
= 312.3 K
Room which is maintained at constant temperature is :
= (22+273) K
= 295 K
The thermal energy transferred to the room is :
Q = 400 kJ
= 
Therefore, the total entropy generation during the thermal energy process is :
![$\Delta S =\left[\frac{-Q}{T_i}+ \frac{+Q}{T_i}\right]$](https://tex.z-dn.net/?f=%24%5CDelta%20S%20%3D%5Cleft%5B%5Cfrac%7B-Q%7D%7BT_i%7D%2B%20%5Cfrac%7B%2BQ%7D%7BT_i%7D%5Cright%5D%24)
Here, -Q = heat is leaving the system maintained at a temperature of 
K.
+Q = heat is entering the system maintained at a temperature of 
K.
Therefore, substituting the values :
![$\Delta S =\left[\frac{-400\times 10^3}{312.3}+ \frac{400\times 10^3}{295}\right]$](https://tex.z-dn.net/?f=%24%5CDelta%20S%20%3D%5Cleft%5B%5Cfrac%7B-400%5Ctimes%2010%5E3%7D%7B312.3%7D%2B%20%5Cfrac%7B400%5Ctimes%2010%5E3%7D%7B295%7D%5Cright%5D%24)
= [-1280.8197 + 1355.9322]
= 75.1125 J/K
= 0.0751125 kJ/K
= 0.075 kJ/K
So we have an equilibrium expression:
CO(g) + 3H2(g) <=> CH4(g) + H2O(g)
The equilibrium expression is the concentration of each product (excluding solids and liquids in all cases) raised to the power of their coefficient, all divided by the concentration of each reactant (again, excluding solids and liquids). Noting that brackets around a molecule indicate concentration, the expression would be:
([CH4]*[H2O])/([CO]*[H2]^3)
The answer is a.commensalism
The rate of dissolution simply tells us how fast or slow a given solute will dissolve in a particular solvent. There are four main factors that affect this rate: temperature, stirring, area of contact, and saturation.
