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vladimir2022 [97]
3 years ago
15

24. What volume of a 0.0200M calcium hydroxide is required to neutralize 35.00 mL of 0.0500M nitric acid

Chemistry
1 answer:
Natalka [10]3 years ago
6 0

Answer:

THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.

Explanation:

Using

Ca VA / Cb Vb = Na / Nb

Ca = 0.0500 M

Va = 35 mL

Cb = 0.0200 M

Vb = unknown

Na = 2

Nb = 1

Equation for the reaction:

Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O

So therefore, we make Vb the subject of the equation and solve for it

Vb = Ca Va Nb / Cb Na

Vb = 0.0500 * 35 * 1 / 0.0200 * 2

Vb = 1.75 / 0.04

Vb = 43.75 mL

The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL

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Is NaBr+I2 -> NaI+Br2 a single replacement
snow_lady [41]

Is not a single replacement

<h3>Further explanation</h3>

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A+BC--> AC+B

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Then the reaction will not occur because I₂ cannot oxidize Br, or the reaction is said to be non-spontaneous

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Why is ionic bonding considered a bond type and an attractive force?
Anika [276]

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Explanation:

7 0
2 years ago
16.1 g of bromine are mixed with 8.42 g of chlorine to give an actual
Sloan [31]

The question is complete, the complete question is;

16.1g of bromine are mixed with 8.42g of chlorite to give an actual yield of 21.1g of bromine monochloride.

Answer:

91 %

Explanation:

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Number of moles of Chlorine = 8.42/71 = 0.119 moles

If 1 mole of Cl2 yields 2 moles of BrCl

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Percentage yield = Actual yield/Theoretical yield * 100

= 21.1/23.07 * 100 = 91 %

3 0
3 years ago
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