First, find the measure of an interior angle:
the sum of the interior angles of a polygon is (n-2)*180, n is the number of sides
for a 15-sided polygon, the sum is 13*180
each interior angle is then 13*180/15=156
the measure of each exterior angle=180-156=24
Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
6x + 10y = 8 ( subtract 6x from both sides )
10y = - 6x + 8 ( divide each term by 10 )
y = -
x +
= -
x 6 +
← in slope- intercept form
with slope m = -
→ C
The time required to get a total amount of $1,000,000.00 with compounded interest on a principal of $5,000.00 at an interest rate of 10% per year and compounded 1 times per year is 55.59 years.
<h3>Given data</h3>
Principal = $5,000
Rate = 10%
Final Amount A= $1,000,000
Time = ?
First, convert R as a percent to r as a decimal
r = R/100
r = 10/100
r = 0.1 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(1,000,000.00/5,000.00) / ( 1 × [ln(1 + 0.1/1)] )
t = ln(1,000,000.00/5,000.00) / ( 1 × [ln(1 + 0.1)] )
t = 55.59 years
(about 55 years 7 months)
Learn more about compounding interest at:
brainly.com/question/1570054
Answer:
(a) (a² +3a -1)(a² -3a -1)
Step-by-step explanation:
The constant term of the product of the factors will be equal to the product of their constants. Since you want that product to be +1, the signs of the factor constants must be the same. That eliminates choices (c) and (d).
__
To tell which of choices (a) and (b) is correct, we can compute the squared term in their product. Let's do it in a generic way, with the constant (±1) being represented by "c".
We want the a² term in the product ...
(a² +3a +c)(a² -3a +c)
That term will be the result of multiplying both sets of first and last terms, and adding the product of the middle terms:
(a²·c) +(a²·c) -9a² = a²(2c-9)
So, we want the factor (2c-9) to be -11, which means c=-1, not +1.
The correct factorization of the given expression is ...
(a² +3a -1)(a² -3a -1) . . . . matches choice A