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2 years ago

A set of scores with a normal distribution has a mean of 50 and a

1 answer:

4 0

36, 43, 50, 57, 64

36 and 64 are two standard deviations out, so the empirical rule tells us 95% of scores will fall here with a normal distribution

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In a jar there are 3 yellow candies, 3 blue candies, and 2 orange candies. What percent of the jar is filled with orange candies

Nastasia [14]

Answer: 25 percent of the jar is filled with orange candies

Step-by-step explanation:

In the jar, there are 3 yellow candies, 3 blue candies, and 2 orange candies. This means that the total number of candies inside the jar would be the sum of the yellow, blue and orange candies. It becomes

3 + 3 + 2 = 8 candies.

The percent of the jar filled with orange candies would be expressed as

number of orange candies/total number of candies × 100

It becomes

2/8 × 100 = 25%

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2 years ago

Find the angle between u= V51 - 8; and v= 151+x. Round to the nearest tenth of a degree.

Igoryamba

Not sure if your trying to solve for x or v

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2 years ago

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scZoUnD [109]

Answer:

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2 years ago

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A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no m

Naddika [18.5K]

Answer:

The null hypothesis is $H_0: p \leq x$ , in which x is the proportion tested.

The alternative hypothesis is $H_1: p > x$

Step-by-step explanation:

A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no more than x.

This means that at the null hypothesis, we test if the proportion is of at most x, that is:

$H_0: p \leq x$

Suppose that we suspect otherwise and carry out a hypothesis test.

The opposite of at most x is more than x, so the alternative hypothesis is:

$H_1: p > x$

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2 years ago

Select the best possible first step to solving the system by first eliminating the x variable.3x − 9y = 6 2x − 11y = 6?

musickatia [10]

$\left\{\begin{array}{ccc}3x-9y=6&|divide\ both\ sides\ by\ 3\\2x-11y=6&|divide\ both\ sides\ by\ (-2)\end{array}\right\\\\\underline{+ \left\{\begin{array}{ccc}x-3y=2\\-x+5.5y=-3\end{array}\right}\\.\ \ \ 2.5y=-1$

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2 years ago

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