Molar mass H2SO4 = 98g/mol
To prepare 5L of a 2.0M solution you require: 98g/mol * 5mol * 2mol /L = 980g H2SO4
Explanation:
The answer is thermal energy/ kinetic energy.. because friction on hands promotes thermal energy. because you want your hands 2 be warm, rubbing them 2gether creates heat and absorption of heat thru the skin which skin is susceptible to warm, humans can put hands under arm pits to warm hands, without any available heat source..
Prokaryotes are organisms whose cells lack a nucleus and other organelles
Answer:
Option (b) 0.67 M
Explanation:
The following Data were obtained from the question:
Mole of MgCl2 = 0.5 mole
Volume of solution = 750mL
Molarity of MgCl2 =?
Next, we shall convert the volume given from mL to L. This is illustrated below:
1000mL = 1L
Therefore 750mL = 750/1000 = 0.75L
Now we can obtain the molarity of MgCl2 as follow:
Molarity is defined as the mole of solute per unit litre of the solution i.e
Molarity = mole /Volume
Molarity = 0.5/0.75
Molarity of MgCl2 = 0.67 M
Answer:
In the original sample there's 72.78% KCl
Explanation:
KCl(aq) + AgNO₃(aq) → AgCl(s) + KNO₃(aq)
- To solve this problem we need to calculate the mass of <em>pure</em> potasssium chloride. To do that we calculate the moles of KCl that reacted into AgCl:
1.26 g AgCl *
- Now with the molecular weight of KCl, we can calculate the mass of KCl that reacted:
8.792 * 10⁻³ mol KCl * 74.55 g/mol = 0.655 g KCl
- Finally we divide the mass of <em>pure</em> KCl by the mass of the sample, to calculate the percentage KCl:
0.655 / 0.900 * 100% = 72.78%