Answer:
The pressure inside the container would increase with each additional pump.
Explanation:
- From the general gas law of ideal gases:
<em>PV = nRT,</em>
where, P is the pressure of the gas.
V is the volume of the gas.
n is the no. of moles of the gas.
R is the general gas constant.
T is the temperature of the gas.
- As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.
<em>P α n.</em>
- As gas particles are pumped into a rigid steel container, the no. of moles of the gas will increase.
So, the pressure of the gas will increase.
<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>
Answer:
514.5 g.
Explanation:
- The balanced equation of the reaction is: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.
- It is clear that every 2.0 moles of NaOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of Na₂SO₄ and 2.0 moles of 2H₂O.
- Since NaOH is in excess, so H₂SO₄ is the limiting reactant.
- We need to calculate the no. of moles of 355.0 g of H₂SO₄:
n of H₂SO₄ = mass/molar mass = (355.0 g)/(98.0 g/mol) = 3.622 mol.
Using cross multiplication:
∵ 1.0 mol H₂SO₄ produces → 1.0 mol of Na₂SO₄.
∴ 3.622 mol H₂SO₄ produces → 3.662 mol of Na₂SO₄.
- Now, we can get the theoretical mass of Na₂SO₄:
∴ mass of Na₂SO₄ = no. of moles x molar mass = (3.662 mol)(142.04 g/mol) = 514.5 g.
The tert-butyl chloride in ethanol would surely react faster than the solvolysis of 1-chloro-2,2-dimethyl propane. It is known that both reactions are under the SN2 category so it would be hard for these reactions to occur. However, SN1 reactions are possible because of the ethanol which is a polar solvent. Both would form carbocations but tert-butyl chloride forms a more stable carbocation while the 1-chloro-2,2-dimethyl propane forms a primary carbocation only.
Answer:
8.5155g NH3
Explanation:
the molar mass of NH3 is 17.031 g/mol
0.5 mol NH3 x 17.031 gNH3/1 mol NH3 = 8.5155g NH3
Answer:
the reaction will shift towards the “heat”—shifts to the left
Explanation:
To summarize:
o If temperature increases (adding heat), the reaction will shift away from the “heat” term and go in the
endothermic direction.
o If temperature decreases (removing heat), the reaction will shift towards the “heat” term and go in the
exothermic direction.
o NOTE: The endothermic direction is always away from the “heat” term and the exothermic direction is
towards the “heat” term.
Therefore the reaction will shift towards the “heat”—shifts to the left