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3 years ago

7

A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many milliliters of water would this brick

displace?

1 answer:

hodyreva [135]3 years ago

7 0

Volume is lxwxh so do 25x12x13

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When heated, KClO3 decomposes into KCl and O2. KClO3--> 2KCl+ 3O . If this reaction produced 62.6 g of KCl, how much O2 was p

Vladimir [108]

The solution to your problem is as follows:

<span>2 KClO3 → 2 KCl + 3 O2

</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole

62.6/74.6 = 0.839 moles KCl produced

0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.

5 0

2 years ago

Identify the single displacement reaction. C4H12 + 7O2 ⟶ 6H2O + 4CO2 2H2 + O2 ⟶ 2H2O Al2S3 ⟶ 2Al + 3S Cl2 + 2KBr ⟶ 2KCl + Br2

Varvara68 [4.7K]

Answer:- $Cl_2+2KBr\rightarrow 2KCl+Br_2$

Explanations:- The first reaction is combustion reaction as the hydrocarbon is burned in presence of oxygen to give carbon dioxide and water.

Second reaction is the synthesis reaction as in general a synthesis reaction looks like:

$A+B\rightarrow AB$

Third reaction is the decomposition reaction as it looks opposite of synthesis reaction.

$AB\rightarrow A+B$

In general, a single displacement reaction looks like:

$AB+C\rightarrow AC+B$

Fourth reaction is single replacement reaction as bromine is replaced by chlorine.

So, the correct choice is the last reaction, $Cl_2+2KBr\rightarrow 2KCl+Br_2$ .

8 0

2 years ago

At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume

Natalija [7]

Answer: Volume would be 196.15 mL if the temperature were changed to $22^{o}C$ and the pressure to 1.25 atmospheres.

Explanation:

Given: $T_{1} = 35^{o}C = (35 + 273) K = 308 K$ , $V_{1}$ = 256 mL,

$P_{1}$ = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

$T_{1} = 22^{o}C = (22 + 273) K = 295 K$ , $P_{2} = 1.25 atm$

Formula used to calculate volume is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL$

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to $22^{o}C$ and the pressure to 1.25 atmospheres.

4 0

2 years ago

What two main characteristics are used to classify air masses

Klio2033 [76]

Temperature and Moisture

8 0

3 years ago

A 0.5 mol sample of He(g) and a 0.5 mol sample of Ne(g) are placed separately in two 10.0 L rigid containers at 25°C. Each conta

KiRa [710]

Answer:

Helum (He)g will escape faster

Explanation:

the phenomemenon can be explained by the Graham's law of diffusion.

Graham's law of difussion states that the rate of difussion is inversely proportional to the square root of the molecular mass,which means the gas with lower molecular mass will escape faster.

Helium gas has a molecular mass of 4 while Neon has a molecular mass of 10.

rate of diffusion of He/rate of difussion of Ne=√4/10=√0.4=0.63

It means He(g) will move 0.63 times faster than Ne(g) under the same condition

5 0

2 years ago