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kipiarov [429]
3 years ago
12

50.00 mL of unknown calcium hydroxide solution is titrated with 0.250 M standard nitric acid solution. If 43.43 mL of the standa

rd acid solution is required to reach a phenolphthalein endpoint, what is the molarity of the unknown calcium hydroxide solution
Chemistry
1 answer:
notsponge [240]3 years ago
5 0

Answer: Molarity of the unknown calcium hydroxide solution is 0.217 M.

Explanation:

Given: V_{1} = 50.00 mL,     M_{1} = ?

V_{2} = 43.43 mL,         M_{2} = 0.250 M

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\M_{1} \times 50.00 mL = 0.250 M \times 43.43 mL\\M_{1} = \frac{0.250 M \times 43.43 mL}{50.00 mL}\\= 0.217 M

Thus, we can conclude that molarity of the unknown calcium hydroxide solution is 0.217 M.

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2.61 kilograms of water in a container have a pressure of 200 kPa and temperature of 200°C . What is the volume of this containe
Arisa [49]

<u>Answer:</u> The volume of the container is 2.8497m^3

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 200 kPa

V = volume of container = ? L

m = Given mass of water = 2.61 kg = 2610 g   (Conversion factor: 1kg = 1000 g)

M = Molar mass of water = 18 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 200^oC=[200+273]K=473K

Putting values in above equation, we get:

200kPa\times V=\frac{2610g}{18g/mol}\times 8.31\text{L kPa }\times 473K\\\\V=2849.7L

Converting this into cubic meter, we use the conversion factor:

1m^3=1000L

So, \Rightarrow \frac{1m^3}{1000L}\times 2849.7L

\Rightarrow 2.8497m^3

Hence, the volume of the container is 2.8497m^3

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