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Paha777 [63]
3 years ago
14

How many atoms are in 8.28 moles of aluminum?

Chemistry
1 answer:
Lilit [14]3 years ago
4 0

Answer:

49.86 × 10²³  atoms of Al

Explanation:

Given data:

Number of moles of Al = 8.28 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.28 moles of Al:

1 mole = 6.022 × 10²³  atoms of Al

8.28 mol×6.022 × 10²³  atoms / 1mol

49.86 × 10²³  atoms of Al

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Answer:

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4 0
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I wanted known how many of the reaction below is energy released
Tema [17]

Answer:

2

Explanation:

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Glucose + oxygen → carbon dioxide + water + 38ATP

2) 2H₂ + O₂   →    2H₂O  ΔH = -486 kj/mol

The given reaction is formation of water. In this reaction oxygen and hydrogen react to form water and 486 kj/mol is also released.

The reaction in which heat is released is called exothermic reaction.

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂   →  CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂   →  CO₂ + 393 Kj/mol

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O   →  CO  + H₂

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it can be written as,

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5 0
3 years ago
Can someone please help me identify these functional groups? Please it’s extremely urgent
sdas [7]

Answer:

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4 0
2 years ago
Assign oxidation states to each atom in each of the following species.?
DochEvi [55]
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3 0
3 years ago
At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
puteri [66]

Answer: The value of K_c is 0.0057

Explanation:

Initial moles of  SO_3 = 0.900 mole

Volume of container = 2.00 L

Initial concentration of SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M  

equilibrium concentration of O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M [/tex]

The given balanced equilibrium reaction is,

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Initial conc.              0.450 M               0        0

At eqm. conc.    (0.450 -2x) M         (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}

K_c=\frac{x\times (2x)^2}{0.450-2x)^2}

we are given : x = 0.055

Now put all the given values in this expression, we get :

K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}

K_c=0.0057

Thus the value of the equilibrium constant is 0.0057

3 0
4 years ago
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