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3 years ago

How many atoms are in 8.28 moles of aluminum?

Chemistry

1 answer:

Lilit [14]3 years ago

4 0

Answer:

49.86 × 10²³ atoms of Al

Explanation:

Given data:

Number of moles of Al = 8.28 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.28 moles of Al:

1 mole = 6.022 × 10²³ atoms of Al

8.28 mol×6.022 × 10²³ atoms / 1mol

49.86 × 10²³ atoms of Al

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Step 1: Data given

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2NH3(aq) + CO2(aq) --> CH4N2O(aq) + H2O(l)

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Moles CO2 = 4803.45 moles

Step 5: Calculate limiting reactant

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For 2 moles NH3 consumed, we need 1 moles of CO2 to produce 1 mole urea and 1 mole H2O

For 7192.77 moles of NH3, we have 3596.4 moles of urea produced

Step 7: Calculate mass of urea

Mass urea = moles urea * molar mass urea

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Mass urea = 216000 grams = 216 kg = theoretical yield

Step 8: Calculate % yield

% yield = (actual yield / theoretical yield)*100%

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The % for this reaction is 78.8 %

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