Answer:
The rate at which bus 1 is going is 55 mph
The rate at which bus 1 is going is 35 mph
Explanation:
As per the question:
Suppose, the distance traveled by Bus 1 be 'd' at the rate R after a time, t = 3h
Thus
Suppose, the distance traveled by Bus 1 be 'd'' at the rate, R'20 mph slower than the rate of Bus 1 after the same time.
R' = R - 20
The distance is given as the product of rate and time:
d = Rt (1)
Now, the total distance given is 270 miles:
d + d' = 270
Now, using eqn (1):
Rt + R't = 270
3(R + R - 20) = 270
6R = 270 + 60
R = 55 mph
R' = R - 20 = 55 - 20 = 35 mph
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Answer: Truck 2, because it has a larger mass than truck 1 (and the same velocity)
Explanation:
We can write the kinetic energy of an object with mass M and velocity V as:
K = (M/2)*V^2
Let's calculate the kinetic energy for each truck:
Now, we can see that both trucks move at the same velocity, but truck 1 has a mass of 5000 pounds, while truck 2 has also a mass of 5000 pounds and an extra of 900 pounds.
Then the total mass of truck 2 is 5000 pounds + 900 pounds = 5900 pounds.
Then both trucks have the same velocity, and truck 2 has a larger mass than truck 1, this implies that truck 2 will have a larger kinetic energy than truck 1.
Answer:
Answer is A
Explanation:
As we know , for constant velocity we get a straight line.
The formula for this problem is s = vt which is similar to a straight line formula like y = mx + c.
If we put here c = 0 we get the formula for distance and velocity.
So the answer is A.
Answer:
third charge must be placed at x = -298.11 cm
Explanation:
When two opposite charges are placed in a straight line then the electric field is always zero at a point near to the charge of lesser magnitude
so here let say the point where electric field is zero lie on the left side of 7.00 micro C charge at a distance "x" from it
so we will have net electric field due to both charges will be zero at that point
so electric field of charge 1 must be equal to the electric field of charge 2
so we have
now square root both sides
so third charge must be placed at x = -298.11 cm
