Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
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Answer:
10.96
Explanation:
<em>A solution is prepared at 25 °C that is initially 0.14 M in diethylamine, a weak base with Kb = 1.3 × 10⁻³, and 0.20 M in diethylammonium chloride. Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
Step 1: Calculate the pOH of the solution
Diethylamine is a weak base and diethylammonium (from diethylammonium chloride) its conjugate acid. Thus, they form a buffer system. We can calculate the pOH of this buffer system using the Henderson-Hasselbach's equation.
pOH = pKb + log [acid]/[base]
pOH = -log 1.3 × 10⁻³ + log 0.20 M/0.14 M
pOH = 3.04
Step 2: Calculate the pH of the solution
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -3.04 = 10.96
Answer:
16.5 dm³
Explanation:
Data Given:
no. moles of O₂ = 0.735 moles
volume of O₂ = ?
Solution:
Now
we have to find volume of O₂ gas
Formula used for this purpose
No. of moles = Volume / molar volume
where
molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol
No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)
Put values in equation 1
0.735 = Volume of O₂ / 22.4 dm³/ mol
rearrange above equation
Volume of O₂ = 0.735 x 22.4 dm³/ mol
Volume of O₂ = 16.5 dm³
So,
the volume of O₂ at STP is 16.5 dm³
