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2 years ago

ASAP hey! i’ll give brainliest please help.

Mathematics

1 answer:

Ainat [17]2 years ago

6 0

Answer:

The Indus River Valley

Step-by-step explanation:

The Persian Empire spanned from Egypt in the west to Turkey in the north, and through Mesopotamia to the Indus River in the east.

If this helped, please give it brainliest!

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Convert 14ML (megalitres) iinto kilolitres

irakobra [83]

Answer:

14000Kilolitres

Step-by-step explanation:

$1megalitre = 1000kilolitres \\$

$14megalitres = xkilolitres$

Cross multiply

$14 \times 1000 = xkilolitres$

$14megaitres = 14000kilolitres$

6 0

2 years ago

What would x be?????

yarga [219]

Answer:

12 cm

Step-by-step explanation:

The square of the length of the tangent segment is equal to the product of near and far distances to the circle from the point of intersection of the secant and tangent:

(8 cm)^2 = (4 cm)(4 cm +x)

16 cm = 4 cm +x . . . . . . divide by 4 cm

12 cm = x . . . . . . . . . . . . subtract 4 cm

6 0

2 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$