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3 years ago

Its A i did it and i got a

Physics

1 answer:

n200080 [17]3 years ago

4 0

Answer:

THATS COOL

Explanation:

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Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile

Nostrana [21]

Answer:

85 miles .

Explanation:

Displacement along the 110 South freeway = 260 - 150 = 110 miles

Displacement along the 110 North freeway = 150 - 175 = - 25 miles

Net displacement = 110 - 25 = 85 miles

So Joey's displacement from the 260 mile marker is 85 miles .

8 0

3 years ago

A pressure wave is what type of wave

Alex777 [14]

propagated disturbance is a variation

5 0

2 years ago

A particle is released as part of an experiment. Its speed t seconds after release is given by v (t )equalsnegative 0.4 t square

torisob [31]

Answer:

a) 2.933 m

b) 4.534 m

Explanation:

We're given the equation

v(t) = -0.4t² + 2t

If we're to find the distance, then we'd have to integrate the velocity, since integration of velocity gives distance, just as differentiation of distance gives velocity.

See attachment for the calculations

The conclusion of the attachment will be

7.467 - 2.933 and that is 4.534 m

Thus, The distance it travels in the second 2 sec is 4.534 m

6 0

3 years ago

Ford used to make a 7.0 liter engine. Calculate how many many cubic inches would be the same size engine.

Anestetic [448]

Answer : The volume of engine in cubic inches is, $427.166\text{ inch}^3$

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

$1\text{ liter}=1000cm^3$

So, $7\text{ liter}=7000cm^3$

$1\text{ inch}=2.54cm$

or,

$1cm=\frac{1}{2.54}\text{ inch}$

$1cm^3=(\frac{1}{2.54}\text{ inch})^3$

As,

$1cm^3=(\frac{1}{2.54}\text{ inch})^3$

So,

$7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3$

Thu, the volume of engine in cubic inches is, $427.166\text{ inch}^3$

3 0

3 years ago

The mass of the Sun is 2 × 1030 kg, the mass of the Earth is 6 × 1024 kg, and their center-to-center distance is 1.5 × 1011 m. S

choli [55]

Answer:

0.00461031264 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of the Earth = 6 × 10²⁴ kg

r = Distance between Earth and Sun = $1.5\times 10^{11}\ m$

t = Time taken = 3 days

Acceleration is given by

$a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(1.5\times 10^{11})^2}\\\Rightarrow a=1.77867\times 10^{-8}\ m/s^2$

Velocity of the star

$v=u+at\\\Rightarrow v=0+1.77867\times 10^{-8}\times 3\times 24\times 60\times 60\\\Rightarrow v=0.00461031264\ m/s$

The Sun's speed will be 0.00461031264 m/s

5 0

3 years ago