Using lens equation;
1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)
Substituting;
1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm
Therefore, the object should be place 99.23 cm from the lens.
Answer:
The relative velocity of an object A with respect to another object B.
Explanation:
The relative velocity of an object A with respect to another object B is the velocity that object A would appear to have to an observer situated on object B moving along with it.
Answer:
It can only display one record at a time
Explanation:
Form ;
1. This is a document with spaces (also called placeholders or fields ) in which a series of documents with similar content can be written or selected.
2.This is the most popular method of data entry
3.It may contain images in the background.
4.This can be sorted data regardless of its source of information.
Only option C is wrong.
Therefore the answer C is correct.
Answer:
Distance: 1600 m Displacement: 0
Explanation:
The distance is because He ran 400 meters 4 times getting 1600 m
4*400=1600
The displacement is 0 because displacement is the total distnce away from the starting point and since he ran laps around the track in the end he ended up in the same spot as last time.
Answer: Symbol is I and unit A
Explanation: A represents Amperes
HOPE THIS HELPS!!!!!!!!
