A spring with spring constant 15.5 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.
1 answer:
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Answer: (a) The magnitude of its temperature change in degrees Celsius is .
(b) The magnitude of the temperature change (change in T = 15.1 K) in degrees Fahrenheit is .
Explanation:
(a) Expression for change in temperature is as follows.
= 15.1 K
=
=
=
Therefore, the magnitude of its temperature change in degrees Celsius is .
(b) Change in temperature from Celsius to Fahrenheit is as follows.
F = 1.8C + 32
C =
Since, K = C + 273
or,
= 1.8 (15.1)
=
or, =
Thus, we can conclude that the magnitude of the temperature change (change in T = 15.1 K) in degrees Fahrenheit is .
Answer:
(a) t = 1.14 s
(b) h = 0.82 m
(c) vf = 7.17 m/s
Explanation:
(b)
Considering the upward motion, we apply the third equation of motion:
where,
g = - 9.8 m/s² (-ve sign for upward motion)
h = max height reached = ?
vf = final speed = 0 m/s
vi = initial speed = 4 m/s
Therefore,
<u>h = 0.82 m</u>
Now, for the time in air during upward motion we use first equation of motion:
(c)
Now we will consider the downward motion and use the third equation of motion:
where,
h = total height = 0.82 m + 1.8 m = 2.62 m
vi = initial speed = 0 m/s
g = 9.8 m/s²
vf = final speed = ?
Therefore,
<u>vf = 7.17 m/s</u>
Now, for the time in air during downward motion we use the first equation of motion:
(a)
Total Time of Flight = t = t₁ + t₂
t = 0.41 s + 0.73 s
<u>t = 1.14 s</u>