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Hatshy [7]
3 years ago
12

I am currently studying about spectrums, difraction Gratings, and many other spectrum. So my question is: What should the Spectr

um of the Moon look like? Justify your answer.
This is the only question I am struggling with...so could you please help me? Many Thanks in the future
Physics
1 answer:
saveliy_v [14]3 years ago
3 0
The spectrum of light from the moon should very strongly resemble the spectrum of sunlight. The reason is that any light from the moon started out from the sun. Any difference in their spectra is only due to the moon absorbing more of some wavelengths and less of others. But since the moon appears colorless gray, we don't expect any particular colors to be strongly absorbed, otherwise the moon would look to be the colors of the light that's left.
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A 100 meter rope is 20 kg and is stretched with a tension of 20 newtons. If one end of the rope is vibrated with small amplitude
dezoksy [38]

Answer:

The velocity waves before rain is 10 m/s

The velocity of wave after the rope soaked up 5 kg more is 8.944 m/s

Solution:

As per the question:

Length of the rope, l = 100 m

Mass of the rope, m = 20 kg

Force due to tension in the rope, T_{r} = 20 N

Frequency of vibration in the rope, f = 10 Hz

Extra mass of the rope after being soaked in rain water, m' = 5 kg

Now,

In a rope, the wave velocity is given by:

v_{w} = \sqrt{\frac{T_{r}}{M_{d}}}         (1)

where

M_{d} = mass density

Mass density before soaking, M_{d} = \frac{m}{l} = \frac{20}{100} = 0.20

Mass density after being soaked, M_{d} = \frac{m + m'}{l} = \frac{25}{100} = 0.25

Initially, the velocity is given by using eqn (1):

v_{w} = \sqrt{\frac{20}{0.20}} = 10 m/s

The velocity after being soaked in rain:

v_{w} = \sqrt{\frac{20}{0.25}} = 8.944 m/s

3 0
3 years ago
What is the type of intermolecular force in methylated spirits
Olin [163]
. Methylated spirits have ethanol as a base but may include methyl alcohol (methanol) as part of the denaturing process.
7 0
3 years ago
What is the marble's range if it is fired horizontally from 1.6 m above the ground?
cupoosta [38]

Answer:

The answer is 6.40 meters.

Explanation:

The speed v = √(2gh)

v = √( 2×9.8×6.4) = 11.2 m/s

After, finding the time it takes to hit the ground from a height of 1.6 meters.

time = √(2H÷g)

time = √(2×1.6÷9.8)

time = 0.5714 seconds.

Horizontal distance is speed × time = 11.2 × 0.5714 = 6.40 meters.

5 0
3 years ago
A cart of mass m = 0.12 kg moves with a speed v = 0.45 m/s on a frictionless air track and collides with an identical cart that
lina2011 [118]

Answer:

0.006075Joules

Explanation:

The final kinetic energy of the system is expressed as;

KE = 1/2(m1+m2)v²

m1 and m2 are the masses of the two bodies

v is the final velocity of the bodies after collision

get the final velocity using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

0.12(0.45) + 0/12(0) = (0.12+0.12)v

0.054 = 0.24v

v = 0.054/0.24

v = 0.225m/s

Get the final kinetic energy;

KE = 1/2(m1+m2)v

KE = 1/2(0.12+0.12)(0.225)²

KE = 1/2(0.24)(0.050625)

KE = 0.12*0.050625

KE = 0.006075Joules

Hence the final kinetic energy of the system is 0.006075Joules

5 0
2 years ago
Gasoline burns in the cylinder of an automobile engine. During the combustion reaction, the production of gas forces the piston
serg [7]

Answer:

\Delta U = 1640 J

Explanation:

As we know by first law of thermodynamics that for ideal gas system we have

Heat given = change in internal energy + Work done

so here we will have

Heat given to the system = 2.2 kJ

Q = 2200 J

also we know that work done by the system is given as

W = 560 J

so we have

\Delta U = Q - W

\Delta U = 2200 - 560

\Delta U = 1640 J

6 0
3 years ago
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