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kumpel [21]
3 years ago
15

How much work is done in accelerating a 2000 kg car from rest to a speed of 30 m/s?

Physics
1 answer:
Otrada [13]3 years ago
8 0
The work done is the same as the amount of energy increase. The formula for kinetic energy is 122
1
2
m
v
2
.

The initial KE of the car is 12(1000)×202=200,000
1
2
(
1000
)
×
20
2
=
200
,
000
joules.

The final KE of the car is 12(1000)×302=450,000
1
2
(
1000
)
×
30
2
=
450
,
000
joules.

The difference between these is the amount of work done: 450,000−200,000=250,000
450
,
000
−
200
,
000
=
250
,
000
joules.
14.2K viewsView upvotes

20



3
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A rope attached to a truck pulls a 180−kg motorcycle at 9.0m/s.The rope exerts a 400−N force on the motorcycle at an angle of 15
steposvetlana [31]

Answer:

115911.09915 J

Unchanged

Decreased

Explanation:

m = Mass of motorcycle = 180 kg

v = Velocity of motorcycle = 9 m/s

F = Force = 400 N

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\theta = Angle above the horizontal = 15°

Work done is given by

W=Fscos\theta\\\Rightarrow W=400\times 300\times cos15\\\Rightarrow W=115911.09915\ J

The work done is 115911.09915 J

It can be seen that the force applied is constant so it does not matter if the speed of the motorcycle changes.

Tension on the rope would be

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7 0
3 years ago
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication
koban [17]

Answer:

r = 4.24x10⁴ km.  

     

Explanation:

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\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}

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From equation (1), r₁ is:

r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}                            

r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}      

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I hope it helps you!

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The total thermal power generated by this plutonium source is determined as 5.65 J/s.

<h3>Total thermal power generated</h3>

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ΔP = 5.65 J/s

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