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Allisa [31]
3 years ago
10

Place test tubes containing approximately equal volumes in opposite positions on the rotor. Wait until all positions on the roto

r contain a test tube before activating the centrifuge. Never put stoppers or other items in the centrifuge with your tubes. Carefully stopper the test tubes to ensure the liquids do not spill out. (b) When operating the centrifuge, students should do which of the following? Make sure that the lid is completely shut and the safety knob is turned to engage the safety switch. Centrifuge for approximately 30 minutes. Centrifuge for approximately 30 seconds. Mid-way through the process, open the lid of the centrifuge and check to be sure it is operating. (c) When the centrifuge process is complete, students should do which of the following? Wait for the rotor to come to a complete stop before attempting to remove your test tubes. Using the eyehole on top, monitor the spinning rate and open the lid only after the rotor has slowed significantly. Immediately open the lid of the centrifuge to remove the test tubes before they are damaged. Reach out and carefully slow the rotor with your hand so you may finish the lab faster.
Engineering
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

do it

Explanation:

they are giving you step by step instructions to do. i woul hate to have to work with you out anywhere in the world if you have to ask this. i am 15, and i would at least read the d a m n thing before i post it.

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Use the predicate specifications(x, y): x beats yF (x): x is an (American) football teamQ(x, y): x is quarterback of yL(x,y): x
attashe74 [19]

Answer:

a) ∀y∃x(Q(x, y))

b) (B(Jayhawks, W ildcats)→¬∀y(L(Jayhawks, y)))

c) ∃x(B(Wildcats, x) ∧ B(x, Jayhawks))

Explanation:

a) The statement can be rewritten as "For all football teams, there exists a quarterback" which is written in logical symbols.

b) The statement is an implication and thus have a premise and a conclusion. The premise states "Jayhawks beat the Wildcats" which is translated using B(x, y). The conclusion can be rewritten as "It is not the case that Jayhawks lose to all football teams".

c) The statement is a simple conjunction which can be written as "There exists a team x such that the Wildcats beats x and x beats Jayhawks"

7 0
3 years ago
Steam enters an insulated turbine at 100 bar, 400oC. At the exit, the pressure and quality are 200 kPa and 0.47, respectively. D
OverLord2011 [107]

Answer:

power produced = 3098.52 kW

Explanation:

given data

insulated turbine = 100 bar

temperature = 400°C

pressure = 200 kPa

mass flow rate = 1.99 kg/s

solution

we use here steam table for At 100 bar and 400°C  

h1 = 3096.5 KJ/Kg

and  

at P2 = 200 Kpa

h2 = hf + 0.47 hg

h2 = 504.7 + 0.47 ×  2201.6  

h2 = 1539.452 KJ/Kg

so here

power produced  is express as

power produced = m × (h1 - h2)    .................1

power produced = 1.99 × ( 3096.5 - 1539.452 )

power produced = 3098.52 kW

8 0
4 years ago
Meeeeep
lesya [120]

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5 0
3 years ago
Read 2 more answers
Suzanne Brett wants to borrow $55,000 from the bank. The interest rate is 6.5% and the term is for 5 years.
Otrada [13]

Answer: $14575

$55000

6.5%

5 years

Total Payment Amount: $72875

Yearly payment :$72875/5= $14575

8 0
2 years ago
End A of the uniform 5-kg bar is pinned freely to the collar, which has an acceleration = 4 m/s2 along the fixed horizontal shaf
sergiy2304 [10]

Answer:

Fa = 57.32 N

Explanation:

given data

mass = 5 kg

acceleration = 4 m/s²

angular velocity ω = 2 rad/s

solution

first we take here moment about point A that is

∑Ma = Iα +  ∑Mad    ...............1

put here value and we get

so here I = ( \frac{1}{12} ) × m × L²    ................2

I = ( \frac{1}{12} ) × 5 × 0.8²

I = 0.267 kg-m²  

and

a  is =  r × α    

a  = 0.4 α

so now put here value in equation is 1

0 = 0.267 α + m r α (0.4) - m A (0.4)

0 = 0.267 α + 5 (0.4α) (0.4 ) - 5 (4) 0.4

so angular acceleration α = 7.5 rad/s²

so here force acting on x axis will be

∑ F(x) = m a(x)    ..............3

a(x) = m a - m rα

put here value

a(x) = 5 × 4 -  5 × 0.4 × 7.5

a(x) = 5 N

and

force acting on y axis will be

∑ F(y) = m a(y)    .............. 4

a(y) - mg = mrω²

a(y) - 5 × 9.81  = 5 × 0.4 × 2²

a(y) = 57.1 N

so

total force at A will be

Fa = \sqrt{a(x)^2+a(y)^2}    ...............5

Fa = \sqrt{(57.1)^2+(5)^2}  

Fa = 57.32 N

3 0
4 years ago
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