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Zinaida [17]
3 years ago
7

Steam enters an insulated turbine at 100 bar, 400oC. At the exit, the pressure and quality are 200 kPa and 0.47, respectively. D

etermine the power produced (kW) by the turbine if the mass flow rate is 1.99 kg/s.
Engineering
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

power produced = 3098.52 kW

Explanation:

given data

insulated turbine = 100 bar

temperature = 400°C

pressure = 200 kPa

mass flow rate = 1.99 kg/s

solution

we use here steam table for At 100 bar and 400°C  

h1 = 3096.5 KJ/Kg

and  

at P2 = 200 Kpa

h2 = hf + 0.47 hg

h2 = 504.7 + 0.47 ×  2201.6  

h2 = 1539.452 KJ/Kg

so here

power produced  is express as

power produced = m × (h1 - h2)    .................1

power produced = 1.99 × ( 3096.5 - 1539.452 )

power produced = 3098.52 kW

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Answer:

C++ code is explained below

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using namespace std;

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void add();

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int main()

{

  int choice;

  cout << "\nMenu";

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  cin >> choice;

 

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  cout << "\nmatrix2 # of columns: ";

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  for(i=0;i<rows2;i++)

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          cout << "\nEnter element (" << i << "," << j << "): ";

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      for(j=0;j<cols2;j++)

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      cout << "\n";

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          for(j=0;j<cols1;j++)

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  int rows1,cols1,i,j,k,rows2,cols2;

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  cout << "\nmatrix1 # of columns: ";

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          cout << "\nEnter element (" << i << "," << j << "): ";

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  cout << "\nmatrix2 # of columns: ";

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