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Zolol [24]
2 years ago
15

Periodic lubrication and oil changes according to manufacturer’s recommendations extend the life of your vehicle, and allow you

to avoid costly repairs, and prevent dangerous breakdowns. Generally, owner's manuals suggest that you change your oil and oil filter every ........... miles. Oil change specialists. however, suggest every ...... miles or ........ months. As you know, most of us do a lot of long distance driving during the summer months when an engine is can overheat. So, you should at least check your oil before you head out on any road trip.
1000, 3000, 2
7,500, 3000, 3
2000, 6000, 4
500,1500, 1
Engineering
1 answer:
Vladimir79 [104]2 years ago
6 0

There are different kinds of rules that applies to engine oils.  Generally, owner's manuals suggest that you change your oil and oil filter every <u>7,500 </u>miles. Oil change specialists. however, suggest every <u>3000 </u>miles or <u>3 </u>months.

<h2>What is Periodic lubrication and oil changes </h2>

Periodic lubrication and oil changes in vehicles is usually done on the advice made by manufacturer. This is often done so as;

  • To make the shelf life of vehicles to be longer .
  • To allow you to not spend your money on unnecessary or costly repairs
  • To prevent dangerous breakdowns on the highways.

It is advisable to always check your owner's manual for the type and when to use lubrications and oil changes and make sure that the right oil/fluid is used for all component.

Learn more about lubrication from

  • brainly.com/question/1142755
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A hemispherical shell with an external diameter of 500 mm and a thickness of 20 mm is going to be made by casting, located entir
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Solution :

Given :

External diameter of the hemispherical shell, D = 500 mm

Thickness, t = 20 mm

Internal diameter, d = D - 2t

                                 = 500 - 2(20)

                                 = 460 mm

So, internal radius, r = 230 mm

                                 = 0.23 m

Density of molten metal, ρ = $7.2 \ g/cm^3$

                                                  = $7200 \ kg/m^3$

The height of pouring cavity above parting surface is h = 300 mm

                                                                                                  = 0.3 m

So, the metallostatic thrust on the upper mold at the end of casting is :

$F=\rho g A h$

Area, A $=2 \pi r^2$

            $=2 \pi (0.23)^2$

            $=0.3324 \ m^2$

$F=\rho g A h$

   $=7200 \times 9.81 \times 0.3324 \times 0.3$

     = 7043.42 N

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Using the celsius_to_kelvin function as a guide, create a new function, changing the name to kelvin_to_celsius, and modifying th
aleksandr82 [10.1K]

Answer:

# kelvin_to_celsius function is defined

# it has value_kelvin as argument

def kelvin_to_celsius(value_kelvin):

   # value_celsius is initialized to 0.0

   value_celsius = 0.0

   

   # value_celsius is calculated by

   # subtracting 273.15 from value_kelvin

   value_celsius = value_kelvin - 273.15

   # value_celsius is returned

   return value_celsius

   

# celsius_to_kelvin function is defined

# it has value_celsius as argument

def celsius_to_kelvin(value_celsius):

   # value_kelvin is initialized to 0.0

   value_kelvin = 0.0

   

   # value_kelvin is calculated by

   # adding 273.15 to value_celsius

   value_kelvin = value_celsius + 273.15

   # value_kelvin is returned

   return value_kelvin

   

value_c = 0.0

value_k = 0.0

value_c = 10.0

# value_c = 10.0 is used to test the function celsius_to_kelvin

# the result is displayed

print(value_c, 'C is', celsius_to_kelvin(value_c), 'K')

value_k = 283.15

# value_k = 283.15 is used to test the function kelvin_to_celsius

# the result is displayed

print(value_k, 'is', kelvin_to_celsius(value_k), 'C')

Explanation:

Image of celsius_to_kelvin function used as guideline is attached

Image of program output is attached.

4 0
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