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Zolol [24]
2 years ago
15

Periodic lubrication and oil changes according to manufacturer’s recommendations extend the life of your vehicle, and allow you

to avoid costly repairs, and prevent dangerous breakdowns. Generally, owner's manuals suggest that you change your oil and oil filter every ........... miles. Oil change specialists. however, suggest every ...... miles or ........ months. As you know, most of us do a lot of long distance driving during the summer months when an engine is can overheat. So, you should at least check your oil before you head out on any road trip.
1000, 3000, 2
7,500, 3000, 3
2000, 6000, 4
500,1500, 1
Engineering
1 answer:
Vladimir79 [104]2 years ago
6 0

There are different kinds of rules that applies to engine oils.  Generally, owner's manuals suggest that you change your oil and oil filter every <u>7,500 </u>miles. Oil change specialists. however, suggest every <u>3000 </u>miles or <u>3 </u>months.

<h2>What is Periodic lubrication and oil changes </h2>

Periodic lubrication and oil changes in vehicles is usually done on the advice made by manufacturer. This is often done so as;

  • To make the shelf life of vehicles to be longer .
  • To allow you to not spend your money on unnecessary or costly repairs
  • To prevent dangerous breakdowns on the highways.

It is advisable to always check your owner's manual for the type and when to use lubrications and oil changes and make sure that the right oil/fluid is used for all component.

Learn more about lubrication from

  • brainly.com/question/1142755
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A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic
DiKsa [7]

Answer:

The answer is below

Explanation:

1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:

n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm

2) The speed of the rotor is the motor speed. The slip is given by:

Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm

3) The frequency of the rotor is given as:

f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz

4) At standstill, the speed of the motor is 0, therefore the slip is 1.

The frequency of the rotor is given as:

f_r=slip*f_s\\f_r=1*60=60\ Hz

6 0
3 years ago
What 2 forces move the secondary piston ahead?
jekas [21]

Answer:

The primary piston activates one of the two subsystems. The hydraulic pressure created, and the force of the primary piston spring, moves the secondary piston forward.

5 0
3 years ago
Compressed Air In a piston-cylinder device, 10 gr of air is compressed isentropically. The air is initially at 27 °C and 110 kPa
Helen [10]

Answer:

(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ

Explanation:

Solution

Recall that:

A 10 gr of air is compressed isentropically

The initial air is at = 27 °C, 110 kPa

After compression air is at = a450 °C

For air,  R=287 J/kg.K

cv = 716.5 J/kg.K

y = 1.4

Now,

(a) W efind the pressure on [MPa]

Thus,

T₂/T₁ = (p₂/p₁)^r-1/r

=(450 + 273)/27 + 273) =

=(p₂/110) ^0.4/1.4

p₂ becomes  2390.3 kPa

So, p₂ = 2.39 MPa

(b) For the increase in total internal energy, is given below:

ΔU = mCv (T₂ - T₁)

=(10/100) (716.5) (450 -27)

ΔU =3030 J

ΔU =3.03 kJ

(c) The next step is to find the total work needed in kJ

ΔW = mR ( (T₂ - T₁) / k- 1

(10/100) (287) (450 -27)/1.4 -1

ΔW = 3035 J

Hence, the total work required is = 3.035 kJ

4 0
3 years ago
Engineering controls are the physical changes that employers make to the work environment or to equipment that make it safer to
____ [38]

Answer:

Engineering Controls. The best engineering controls to prevent heat-related illness is to make the work environment cooler and to reduce manual workload with mechanization. A variety of engineering controls can reduce workers' exposure to heat: Air conditioning, Increased general ventilation , Cooling fans , Local exhaust ventilation at points of high heat production or moisture, Reflective shields to redirect radiant heat , Insulation of hot surfaces Elimination of steam leaks , Cooled seats or benches for rest breaks , Use of mechanical equipment to reduce manual work, Misting fans that produce a spray of fine water droplets.

Hope this helped you!

Explanation:

5 0
3 years ago
In almost all cases, touching power lines or coming into contact with energized sources will result in what?
Fynjy0 [20]

Answer:

electrocution

Explanation:

You will end up getting shoked because the electricity is attracted to the water in your body.

6 0
3 years ago
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