Gumballs cost $0.50 each, and jawbreakers cost $0.30 each. Bob has $3.00 to spend on candy.

Mathematics

1 answer:

KIM [24]2 years ago

3 0

Answer:

0.5x+0.3y >= 3

sorry I don't know how to make the less than or equal to sign

Step-by-step explanation:

he can buy X amount of gumballs if he buys Y amount of jawbreakers and that will be less than or equal to $3

to graph, you must plug the number 0 into the X spot and solve.

0.5(0) +0.3y >= 3

next plug in for Y

0.5x+0.3(0) >= 3

plot these two points on the graph and draw a line through them

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olasank [31]

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3 years ago

A bag holds 11 beads. 7 are red, the rest are white. Two beads are taken at random from the bag. What is the proba polity that o

olasank [31]

Probability that one bead of each colour is taken from $\bold{\frac{14}{55}}$ .

Solution: 

Given that

Total number of Beds = 11

Number of red beds = 7

Number of white beds = 11 – 7 = 4

Two beads are taken at random from the bag. Need to find the probability that one bead of each colour is taken.

$\text { Probability of getting red bed }=\frac{\text { number of red beds }}{\text { total number of beds }}=\frac{7}{11}$

$\text { Probability of getting a white after first one is red }=\frac{\text { number of white beds }}{( \text { total number of beds-1) } }=\frac{4}{10}$

So probability that one bead of each colour is taken = Probability of getting red bed multiplied by Probability of getting a white after first one is red

$\Rightarrow \frac{7}{11} \times \frac{4}{10}=\frac{28}{110}=\frac{14}{55}$