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3 years ago

5

An empty parallel plate capacitor is connected between the terminals of a 18.8-V battery and charges up. The capacitor is then d

isconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor

1 answer:

Basile [38]3 years ago

7 0

Answer:

$p.d' = 37.6 V$

Explanation:

From the question we are told that:

Potential difference $p.d=18.8V$

New Capacitor $C_1=C_2/2$

Generally the equation for Capacitor capacitance is mathematically given by

$C=\frac{eA}{d}$

Generally the equation for New p.d' is mathematically given by

$C_2V=C_1*p.d'$

$p.d' = 2V$

$p.d'= 2 * 18.8$

$p.d' = 37.6 V$

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Answer:

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