Question

Two cars, one in front of the other, are traveling down the highway at 53.7 m/s. The car behind sounds its horn, which has a frequency of 536 Hz. What is the frequency heard by the driver of the lead car

Answer 1

Answer:

Explanation:

The source is approaching the observer which is moving away from the source , so applying Doppler's effect

$n = n_o\frac{V-V_O}{V-V_S}$

where n is apparent frequency , n₀ is original frequency , V₀ is velocity of observer , V_S is velocity of source , V is velocity of sound

Putting the given values

= $n = 536\frac{340-53.7}{340-53.7 }$

= 536

So apparent frequency will be same as original frequency .

ie 536 .