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Romashka-Z-Leto [24]
3 years ago
10

What are the effects of radiation on different surfaces such as an ice- covered lake, a forest, an ocean, or an asphalt road?

Physics
2 answers:
jarptica [38.1K]3 years ago
4 0

Answer:

it could kill the fish in water

My name is Ann [436]3 years ago
4 0
The trees would soak up radiation and also emit it leaving it dangerous to be around, if we are talking about an ice covered lake im not so sure but and un frozen lake would keep in radiation much more than emitting it which is why most nuclear power plants have the plutonium in i believe at least 15 to 20 feet of water and an asphalt road would probably just not be practical because anything else around it would also be radioactive. After a fallout storm you literally need to dig at least 8 feet in order to grow crops again or you will most likely get horribly sick from eating the food it grows
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I have a problem in this questions?
photoshop1234 [79]

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

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Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

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26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

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r = 84.6 m

r = 8.46E+1 m

7 0
2 years ago
A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is
Umnica [9.8K]

The frequency of note C3 is 131 s^{-1}.

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

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Thus,

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