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3 years ago

What are the effects of radiation on different surfaces such as an ice- covered lake, a forest, an ocean, or an asphalt road?

Physics

2 answers:

jarptica [38.1K]3 years ago

4 0

Answer:

it could kill the fish in water

My name is Ann [436]3 years ago

4 0

The trees would soak up radiation and also emit it leaving it dangerous to be around, if we are talking about an ice covered lake im not so sure but and un frozen lake would keep in radiation much more than emitting it which is why most nuclear power plants have the plutonium in i believe at least 15 to 20 feet of water and an asphalt road would probably just not be practical because anything else around it would also be radioactive. After a fallout storm you literally need to dig at least 8 feet in order to grow crops again or you will most likely get horribly sick from eating the food it grows

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Select the three correct parts that make up the cell theory.

Lana71 [14]

Answer:

Options A, D and E....make up cell theory

8 0

3 years ago

Consider the position vs. time graph below for a woman's movement in a hallway. What is the woman's velocity from 4 to 5 s?

Ksenya-84 [330]

Answer:

The answer is " $6\ \frac{m}{s}$ "

Explanation:

The formula for velocity:

$\to \overline{v}={\frac{\Delta x}{\Delta t}}$

$=\frac{6}{1}\\\\=6\ \frac{m}{s}$

7 0

3 years ago

A 71 kW radio station broadcasts its signal uniformly in all directions. - What is the average intensity of its signal at a dist

marshall27 [118]

Answer:

Explanation:

Energy of signal being radiated per second on all sides = 71 x 10³ J .

At a distance of 220 m it is spread over an area of 4 π x (220)² because it is spreading uniformly on all sides.

So energy crossing per unit area

= $\frac{71\times10^3}{4 \times \pi\times(220)^2}$

= 11.67 x 10⁻² Wm⁻²s⁻¹.

This is the intensity of the signal.

At 2200 m this intensity will further reduce by 100 times

So there it becomes equal to

11.67 x 10⁻⁴ Wm⁻² s⁻¹.

3 0

3 years ago

A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east.

Anna71 [15]

Answer:

Time, t = 12 minutes

Explanation:

It is given that,

A cyclist rides 16.0 km east, then 8.0 km west, then 8.0 km east, then 32.0 km west, and finally 11.2 km east. Let west direction is negative and east direction is positive. The displacement of the cyclist is :

$d=16-8+8-32+11.2=-4.8\ km$

d = 4800 m

Let us assumed that the average speed of the cyclist is, v = 24 km/h = 6.66667 m/s

Let t is the time taken by the cyclist to complete the trip. The velocity of an object is given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{4800\ m}{6.66667\ m/s}$

t = 719.99 seconds

t = 720 seconds

t = 12 minutes

So, the time taken by the cyclist to complete the trip is 12 minutes. Yes, the time taken by the cyclist to complete the trip is reasonable. Hence, this is the required solution.

7 0

4 years ago

An object is launched with a vertical velocity of 44.3 m/s upward, and a horizontal velocity of 12 m/s. What is the maximum heig

Brrunno [24]

b is the answer there you go if you need the answer

7 0

3 years ago