Answer:
0.643 mol.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 4.0 atm).
V is the volume of the gas in L (V = 4000 mL = 4.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 30ºC + 273 = 303 K).
<em>∴ n = PV/RT </em>= (4.0 atm)(4.0 L)/(0.0821 L.atm/mol.K)(303 K) = <em>0.643 mol.</em>
The C=O stretch appears as a very sharp and intense peak in an IR spectrum. Since, C=O is a double bond, it appears in the "double bond" region of the IR spectrum, which is typically in the 1500-2000 cm-1 range. More specifically, C=O generally falls in the range of 1650-1850 cm-1. The reason for the range is that there are many types of functional groups that contain a carbonyl (C=O), such as a ketone, aldehyde, amide, or ester. Each of these will have a slightly different value as each stretch will have a different energy due to various factors such as conjugation.
The number of O atoms that ate in 1.25 mol of SO2 is 2.5 moles
<em><u>calculation</u></em>
moles of O= total number O atoms in SO2 x 1.25 moles
The number of O atoms in SO2 = 1 x2 = 2 atoms
moles is therefore= 2 x 1.25 moles = 2.5 moles