Answer:
i. The height of its jump is approximately 0.115 m
ii. The time of flight of its jump is approximately 0.306 seconds
iii. The range of its jump is approximately 0.795 m
Explanation:
The angle at which the grasshopper jumps, θ = 30°
The speed with which the grasshopper takes off, u = 3 m/s
i. The height of its jump 'h', is given by the following relation;
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
The height of its jump, h ≈ 0.115 m
ii. The time of flight of its jump, 't', is given as follows;
Therefore;
The time of flight of its jump, t ≈ 0.306 seconds
iii. The range of the jump is given by the following projectile motion equation for the range as follows;
Therefore;
The range of the jump, R ≈ 0.795 m.
First determine the formal oxidation numbers:
N changes from +2 to +5 going from NO to (NO3)- O remains -2 the whole time Cr changes from +6 to +3
Now write the half reactions, balance the oxygens with the required number of waters and then balance the hydrogens with the required number of protons:
Oxidation half reaction:
NO(aq) + 2 H2O(l) ---> (NO3)-(aq) + 4 H+(aq) + 3 e-
Reduction half reaction:
(Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l)
Now balance the number of electrons on both sides and add them together:
2 NO(aq) + 4 H2O(l) ---> 2 (NO3)-(aq) + 8 H+(aq) + 6 e- (Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l) --------------------------------------... 2 NO(aq) + (Cr2O7)2-(aq) + 6 H+(aq) ---> 2 (NO3)-(aq) + 2 Cr3+(aq) + 3 H2O(l)
Notice that the charge is the same in both sides, which is an indication that the redox equation has been balanced correctly:
-2 + 6 = -2 + 2(+3) +4 = +4
Is similar to 3 an you nedd múltiple by 5 and you get 15 for the result
Answer:
∇T = 51.68°C
Explanation:
Mass = 150g
Heat Energy (Q) = 1.0*10³J
Change in temperature ∇T = ?
Q = mc∇T
Q = heat energy
M = mass
C = specific heat capacity of the gold = 0.129j/g°C
∇T = change in temperature
Q = Mc∇T
1.0*10³ = 150 * 0.129 * ∇T
1000 = 19.35∇T
Solve for ∇T
∇T = 1000 / 19.35
∇T = 51.679°C = 51.68°C
The change in temperature of gold was 51.68°C