Answer:
Eqv Pt pH = 8.73
Explanation:
HOAc + NaOH => NaOAc + H₂O
50ml(0.10M HOAc) + 50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O
For neutralized system, 100ml of 0.05M NaOAc remains
NaOAc => Na⁺ + OAc⁻
Na⁺ + H₂O => No Rxn
OAc⁻ + H₂O => HOAc + OH⁻
C(i) 0.05M ----- 0M 0M
ΔC -x ----- +x +x
C(f) 0.05-x
≅ 0.05M ----- x x
Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)
=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M
=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27
pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH
Answer: when two atoms do not share electrons equally in a covalent bond.
Explanation:
Answer and Explanation:
Elements : 
these are not compounds because for making compound there should be at least combination of two different elements but are made up of same type of elements so these are elements
Compounds: 
these all are compound because they are made up of different types of elements after combining together
Answer:
The answer of a is 5.45% and b is 3.64%
Explanation:
Density of water = 1 g/mL
∴ Mass of water (solvent) = 500 g
Mass of solute (glucose) = 30 g
Mass of solute (common salt) = 20g
Mass of solution = (30 + 20 + 500) g = 550 g
<h2>a.) </h2>
Mass percentage of solution for glucose
= Mass of solute (gucose)/Mass of solution × 100
= 30/550 x 100
= 5.45 %
<h2>b.) </h2>
Mass percentage of solution for common salt
= Mass of solute (common salt)/Mass of solution × 100
= 20/550 × 100
= 3.64 %
Thus, The answer of a is 5.45% and b is 3.64%
<u>-</u><u>The</u><u>U</u><u>nknown</u><u>S</u><u>cientist</u><u> </u><u>72</u>
