Answer:
9.78 m/s²
Explanation:
To solve this, we use the gravitational formula
g = GM/r², where
g = acceleration due to gravity
G = gravitational constant
M = mass of the planet
r = radius of the planet
From the question, we got that the mass of the planet is
M = 9ME, where ME = 5.95*10^24
M = 9 * 5.95*10^24
M = 5.355*10^25 kg
Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6
R = 3 * 6.37*10^6
R = 1.911*10^7 m
On applying the values of both R and M to the equation, we get
g = GM/r²
g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²
g = 3.57*10^15/3.65*10^14
g = 9.78 m/s²
Therefore, the acceleration due to gravity on the planet is 9.78 m/s²
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Answer:
3.75 m/s
Explanation:
From the question given above, the following data were obtained:
Acceleration (a) = 1.5 m/s²
Initial velocity (u) = 0 m/s
Time (t) = 2.5 s
Final velocity (v) =?
a = (v – u) / t
1.5 = (v – 0) / 2.5
1.5 = v / 2.5
Cross multiply
v = 1.5 × 2.5
v = 3.75 m/s
Hence, the escape velocity of the squirrel is 3.75 m/s
Decreases, stays the same, increases.
The volume decreases because as air is cooled, the individual molecules collectively possess less kinetic energy and the distances between them decrease, thus leading to a decrease in the volume they occupy at a certain pressure (please note that my answer only holds under constant pressure; air, as a gas, doesn't actually have a definite volume).
The mass stays the same because physical processes do not create or destroy matter. The law of conservation of mass is obeyed. You're only cooling the air, not adding more air molecules.
The density decreases because as the volume decreases and mass stays the same, you have the same mass occupying a smaller volume. Density is mass divided by volume, so as mass is held constant and volume decreases, density increases.
<u>Answer:</u>
Ball will move 92.8125 meter along the cliff in 7.5 seconds.
<u>Explanation:</u>
We have equation of motion , 
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this case initial velocity = 0 m/s, acceleration = 3.3 
, we need to calculate displacement when time = 7.5 seconds.
Substituting
So ball will move 92.8125 meter along the cliff in 7.5 seconds.
