We need to see what forces act on the box:
In the x direction:
Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.
In the y direction:
N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force.
From N-Gcosα=0 we get:
N=Gcosα, we will need this for the force of friction.
Now to solve for Fh:
Fh=ma + Ff + Gsinα,
Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²
Fh=ma + μmgcosα+mgsinα
Now we plug in the numbers and get:
Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N
The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
Answer:
Option (C) is the answer
Explanation:
may be it is possible if that we stand so far
Here is the correct answer that would best complete the given statement above. The heater in the thermostat control circuit in the cooling mode is active when the <span>heat anticipator in the thermostat control circuit is in the heating mode. Hope this is the answer that you are looking for. </span>
When object is moving in circular path then if suddenly its force reduced to zero then it will move to straight line
This is defined by Newton's First Law
So as per first law of Newton we can say
When there is no net force on an object then it will continue its state of motion in its original state without any change in it.
This is also known as law of inertia
so correct answer will be
Newton's 1st law
Answer:
KE = 9.6MeV
Explanation:
Given the relationships we understand that,
The Potential at point p, is given by the following formula
According to the graphic designed, you have,
The kinetic energy of the particle would be given by
