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vivado [14]
4 years ago
6

Most clouds form in the atmosphere when moist air 1. rises,expands,and cools to the dewpoint 2. rises, expands, and warms to the

dewpointt
Physics
1 answer:
earnstyle [38]4 years ago
4 0
Most clouds form in the atmosphere when moist air rises expands and cool to the dew point. When the air above reaches its saturation point, the water vapor is attracted to dust particles which when they accumulate the hold on tho each other and form clouds. Evaporation and condensation is what causes saturation above. When the clouds become heavy enough with moisture, the water then fall to earth as rain. <span />
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Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°C 50C water. (C = .5 for ice, C 1 for water,
Nitella [24]

<u>Answer:</u> The amount of heat needed is 29000 Cal.

<u>Explanation:</u>

The process involved in this problem are:

(1):H_2O(s)(-30^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(50^oC)

Now, we calculate the amount of heat released or absorbed in all the processes.

  • <u>For process 1:</u>

q_1=mC_{p,s}\times (T_2-T_1)

where,

q_1 = amount of heat absorbed = ?

m = mass of ice = 200 g

T_2 = final temperature = 0^oC

T_1 = initial temperature = -30^oC

Putting all the values in above equation, we get:

q_1=200g\times 0.5Cal/g^oC\times (0-(-30))^oC=3000Cal

  • <u>For process 2:</u>

q_2=m\times L_f

where,

q_1 = amount of heat absorbed = ?

m = mass of water or ice = 200 g

L_f = latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

q_2=200g\times 80Cal/g=16000Cal

  • <u>For process 3:</u>

q_3=m\times C_{p,l}\times (T_{2}-T_{1})

where,

q_3 = amount of heat absorbed = ?

m = mass of water = 200 g

T_2 = final temperature = 50^oC

T_1 = initial temperature = 0^oC

Putting all the values in above equation, we get:

q_3=200g\times 1Cal/g^oC\times (50-0)^oC=10000Cal

Calculating the total heat absorbed, we get:

Q=q_1+q_2+q_3

Q=3000+16000+10000=29000Cal

Hence, the amount of heat needed is 29000 Cal.

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