Question

How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?

Answer 1

Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

$Mg + 2HCl \rightarrow MgCl_{2} + H_{2}$

This shows that 1 mole of Mg gives 1 mole of $H_{2}$.

Hence, moles of Mg for the given mass is calculated as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol$

Hence, 0.095 moles of Mg will give 0.095 moles of $H_{2}$.

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

$PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L$

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.