Answer:
211.63 g.
Explanation:
- Particles could refer to atoms, molecules, formula units.
- <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>
<em><u>Using cross multiplication: </u></em>
1.0 mole → 6.022 x 10²³ molecules.
??? mole → 8.95 x 10²³ molecules.
- The no. of moles of magnesium acetate = (8.95 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 1.486 mol.
∴ The grams of magnesium acetate are in 8.95 x 10²³ formula units = n x molar mass = (1.486 mol)(142.394 g/mol) = 211.63 g.
<u>Answer:</u> The volume of water required is 398 mL
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g
Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol
Molarity of solution = 0.16 M
Putting values in above equation, we get:
Hence, the volume of water required is 398 mL
Concentration "molarity" of H₂SO₄ in this solution:
5 × 10⁻³ mol / dm³.
<h3>Explanation</h3>
What's the concentration of H⁺ ions in this solution?
![[\text{H}^{+}] = 10^{-\text{pH}}](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-%5Ctext%7BpH%7D%7D)
,
where ![[\text{H}^{+}]](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D)
is in the unit mol / dm³.
![[\text{H}^{+}] = 10^{-2} \;\text{mol}\cdot\text{dm}^{-3}](https://tex.z-dn.net/?f=%5B%5Ctext%7BH%7D%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-2%7D%20%5C%3B%5Ctext%7Bmol%7D%5Ccdot%5Ctext%7Bdm%7D%5E%7B-3%7D)
.
What's the concentration "molarity" of H₂SO₄ in this solution?
Sulfuric acid H₂SO₄ is a strong acid. Note the subscript "2". Each mole of this acid dissolves in water to produce two moles of H⁺ ions. It takes only 
of H₂SO₄ to produce twice as much H⁺ ions.
As a result, the <em>molarity</em> of H₂SO₄ is 5 × 10⁻³ mol / dm³ or 0.005 M.
Answer:
PN₂ = 191.3 Kpa
Explanation:
Given data:
Total pressure of tire = 245.0 Kpa
Partial pressure of PO₂ = 51.3 Kpa
Partial pressure of PCO₂ = 0.10 Kpa
Partial pressure of others = 2.3 Kpa
Partial pressure of PN₂ = ?
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = PO₂ + PCO₂ + P(others)+ PN₂
245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂
245 Kpa = 53.7 Kpa+ PN₂
PN₂ = 245 Kpa - 53.7 Kpa
PN₂ = 191.3 Kpa
