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olga55 [171]
3 years ago
11

A baseball has 5.8kg*m/s momentum before being hit by the bat. After being hit it has 6.79 kg*m/s in the opposite direction. Wha

t is the magnitude of the impulse applied to the baseball?​
Physics
1 answer:
fomenos3 years ago
8 0

Answer:

0.99kgm/s

Explanation:

Given parameters:

Initial momentum  = 5.8kgm/s

Final momentum  = 6.79kgm/s

Unknown:

Magnitude of the impulse applied to the baseball  = ?

Solution:

To solve this problem;

 The impulse applied to the baseball can be found by using the expression below:

 Impulse  = Final momentum   -   Initial momentum

Impulse  = 6.79kgm/s - 5.8kgm/s  = 0.99kgm/s

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If a road does not have a bicycle lane, where must a bicyclist ride their bicycle?
DIA [1.3K]
A bicyclist can ride their bicycle still on the road. Bicycle riders be able to take the public ways which has the similar rights and accountability as motorists and are subject to the same guidelines and protocols. The law says that individuals who ride bikes should ride as nearby to the right side of the road as likely excluding under the following conditions: when passing, preparing for a left go, evading risks, if the lane is too constricted to share, or if oncoming a place where a right turn is approved. In a road which has a bike lane the bicyclists roving slower than road traffic must custom the bike way excluding when creating a left turn, passing, evading hazardous settings, or impending a place where a right turn is approved. 
5 0
4 years ago
A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up
Snezhnost [94]

Answer:

Maximum height of rocket  = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

          s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

         v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

Time of flying after 5 seconds

          t=\frac{200}{9.81}=20.38s

Distance traveled in this 20.38 s

          s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m

Maximum height of rocket = 500 +2038.74 = 2538.74 m

6 0
3 years ago
Tasha has mass 20 kg and wants to use a 4.0-m board of mass 10 kg as a seesaw. her friends are busy, so tasha seesaws by herself
ELEN [110]
The 4 m board's center of mass is 2 m so the pivot point is somewhere between Tasha and 2 m (if you draw a picture it's going to make this clearer)

 The mass of Tasha * her distance from the pivot point = the board's mass * distance from the pivot point. 
<span> Let d1 be the distance Tasha is from the pivot point. The board's center of mass from the pivot point is 2 m - d1 
</span><span> 20 kg * d1 = 10 kg * (2m - d1) 
</span><span> Solve for d1, you should get 2/3 of a m for the distance Tasha is from the pivot or support point. The center of mass for the board is 1 1/3 m from the support point. </span>
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HACTEHA [7]
The answer is B as all the other options contain quantities not related to describing motion
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They look like tiny cubes. They are in a cubic form.


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