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goldenfox [79]
3 years ago
7

2. Periodic Table Layout. The periodic table is organized in horizontal rows and also in vertical

Chemistry
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:

Explanation:

Columns and rows used in the periodic classification of elements shows trends in the properties of elements.

The periodic columns are called groups and they denote vertical arrangement of elements.

The horizontal rows are the periods.

  • Groups and Periods provides a very simple way to classify elements.
  • They reflect trends among different elements that are found in nature. Following these groups and periods, it is even possible to predict the nature of an undiscovered element.
  • Certain parts of the table have some unique elements on them with some distinctive properties that distinguish them from others.
  • The atomic number is the basis of this classification. By this, it is possible to delineate that elements with similar properties are located on the same group.
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What is the vapor pressure (in kPa) of ethanol, CH3CH2OH, over a solution which is composed of 18.00 mL of ethanol and 12.55 g o
ladessa [460]

Answer:

The vapor pressure of ethanol in the solution is 10,27 kPa

Explanation:

To obtain the vapor pressure of a solution it is necessary to use Raoult's law:

P_{solution} = X{solvent}P_{0solvent} <em>(1)</em>

The moles of ethanol are:

18,00mL×\frac{0,789g}{1mL}×\frac{1 mol}{46,07g} = 0,3083 mol Ethanol.

Moles of benzoic acid:

12,55 g×\frac{1mol}{122,12g} = 0,1028 mol benzoic acid.

Thus, mole fraction of solvent, X, is:

\frac{0,3083 mol}{0,3083mol+0,1028mol} =<em> 0,7499</em>

Replacing this value in (1):

P_{solution} = 0,7499*13,693kPa = <em>10,27 kPa</em>

<em></em>

I hope it helps!

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3. A 240 mL sample of argon gas at 270 K is cooled until the volume is 180 mL. What is the new temperature?
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4 0
3 years ago
How many moles of copper are there in 6.93 g of copper sample<br>pls be quick​
Alex_Xolod [135]
  • Molar mass of copper=63.5g/mol
  • Given mass=6.93g

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}

\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles

7 0
2 years ago
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