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borishaifa [10]
3 years ago
12

What is the molarity of a 5 L solution that contains 7.5 moles of NaOH?

Chemistry
1 answer:
Aneli [31]3 years ago
5 0

Answer:1.5 M

Explanation:

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The primary forces of attraction between water molecules in H2O(l) are
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The answer is Hydrogen bonds
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The empirical formula of a compound is CH3- The molecular formula of this compound could be C2H6 CH4 C3H6 C2H4
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C2H6

Explanation:

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3 years ago
Answer the following questions:
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Answer:

the melting point is the factor what what degrees fahrenheit a metal or other solid substance melts. the significance of knowing the melting point can help you determine how long or how hot to burn the tested object while at the same time determining the safety requirements.

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A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
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Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of metal = 129.00 g

m_2 = mass of water = 45.00 g

T_f = final temperature = 39.6^oC

T_1 = initial temperature of metal = 97.8^oC

T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

4 0
3 years ago
Calculate the number of moles of sulfuric acid in the total volume you used in the lab (i.e., 8.00 mL). Hint: Use the methodolog
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Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

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